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An A.P. consists of 50 terms of which 3rd term is 12 and the last term is 106. Find the 29th term.?
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An A.P. consists of 50 terms of which 3rd term is 12 and the last term...
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An A.P. consists of 50 terms of which 3rd term is 12 and the last term...
Hi ,


Let a , d are first term and common


difference of an A.P


---

nth term = Last term = a + ( n - 1 )d


an = a + ( n - 1 )d


---


Now ,


It is given that ,


Third term = 12


a + 2d = 12 ---( 1 )


Last term = 106


a + 49d = 106 ---( 2 )


Subtract ( 1 ) from ( 2 ) , we get


47d = 94


d = 2


Substitute d value in equation ( 1 ) ,


We get


a + 2 � 2 = 12


a = 12 - 4


a = 8


29th term = a + 28d


a29 = 8 + 28 � 2


= 8 + 56


= 64


I hope this helps you.


: )
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An A.P. consists of 50 terms of which 3rd term is 12 and the last term is 106. Find the 29th term.?
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