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A man walks on a straight road from his home to a market 2.5 km away with a speed of 5kmph. Finding the market closed, he instantly turns and walks back home with a speed of 7.5kmph. The average speed of the man over the interval of time 0 to 40min is equal to?
Most Upvoted Answer
A man walks on a straight road from his home to a market 2.5 km away w...
Hi sravanthi
we get time to reach market is 2.5/5 = 1/2 or 30 mins
time taken to return is 2.5/7.5 = 1/3 or 20 mins
also in return he travels 1.25 km in 10 mins
now , avg speed = total distance/ total time( for 40min
2.5 + 1.25 /(40/60) = 45/8 km/hr
we get time to reach market is 2.5/5 = 1/2 or 30 mins
time taken to return is 2.5/7.5 = 1/3 or 20 mins
also in return he travels 1.25 km in 10 mins
now , avg speed = total distance/ total time( for 40min
2.5 + 1.25 /(40/60) = 45/8 km/hr
Community Answer
A man walks on a straight road from his home to a market 2.5 km away w...
Problem: Find the average speed of a man who walks from his home to a market 2.5 km away with a speed of 5 kmph and back home with a speed of 7.5 kmph, over the interval of time 0 to 40 minutes.
Solution:
To find the average speed of the man over the given interval of time, we need to first calculate the distance traveled and the time taken for the entire journey.
Step 1: Distance traveled from home to market and back
Distance from home to market = 2.5 km
Total distance traveled = Distance from home to market + Distance from market to home = 2.5 km + 2.5 km = 5 km
Step 2: Time taken for the entire journey
Time taken to travel from home to market = Distance/Speed = 2.5/5 = 0.5 hours = 30 minutes
Time taken to travel from market to home = Distance/Speed = 2.5/7.5 = 1/3 hours = 20 minutes
Total time taken for the entire journey = Time taken to travel from home to market + Time taken to travel from market to home = 30 minutes + 20 minutes = 50 minutes
Step 3: Average speed of the man over the interval of time 0 to 40 minutes
We need to find the average speed of the man over the first 40 minutes of the journey.
Distance covered in the first 40 minutes = Speed x Time = 5 x (40/60) = 200/60 = 10/3 km
Time taken to cover this distance = 40 minutes
Average speed = Distance/Time = (10/3)/(40/60) = 5 kmph
Therefore, the average speed of the man over the interval of time 0 to 40 minutes is 5 kmph.
Solution:
To find the average speed of the man over the given interval of time, we need to first calculate the distance traveled and the time taken for the entire journey.
Step 1: Distance traveled from home to market and back
Distance from home to market = 2.5 km
Total distance traveled = Distance from home to market + Distance from market to home = 2.5 km + 2.5 km = 5 km
Step 2: Time taken for the entire journey
Time taken to travel from home to market = Distance/Speed = 2.5/5 = 0.5 hours = 30 minutes
Time taken to travel from market to home = Distance/Speed = 2.5/7.5 = 1/3 hours = 20 minutes
Total time taken for the entire journey = Time taken to travel from home to market + Time taken to travel from market to home = 30 minutes + 20 minutes = 50 minutes
Step 3: Average speed of the man over the interval of time 0 to 40 minutes
We need to find the average speed of the man over the first 40 minutes of the journey.
Distance covered in the first 40 minutes = Speed x Time = 5 x (40/60) = 200/60 = 10/3 km
Time taken to cover this distance = 40 minutes
Average speed = Distance/Time = (10/3)/(40/60) = 5 kmph
Therefore, the average speed of the man over the interval of time 0 to 40 minutes is 5 kmph.
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A man walks on a straight road from his home to a market 2.5 km away with a speed of 5kmph. Finding the market closed, he instantly turns and walks back home with a speed of 7.5kmph. The average speed of the man over the interval of time 0 to 40min is equal to?
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A man walks on a straight road from his home to a market 2.5 km away with a speed of 5kmph. Finding the market closed, he instantly turns and walks back home with a speed of 7.5kmph. The average speed of the man over the interval of time 0 to 40min is equal to? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A man walks on a straight road from his home to a market 2.5 km away with a speed of 5kmph. Finding the market closed, he instantly turns and walks back home with a speed of 7.5kmph. The average speed of the man over the interval of time 0 to 40min is equal to? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A man walks on a straight road from his home to a market 2.5 km away with a speed of 5kmph. Finding the market closed, he instantly turns and walks back home with a speed of 7.5kmph. The average speed of the man over the interval of time 0 to 40min is equal to?.
A man walks on a straight road from his home to a market 2.5 km away with a speed of 5kmph. Finding the market closed, he instantly turns and walks back home with a speed of 7.5kmph. The average speed of the man over the interval of time 0 to 40min is equal to? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A man walks on a straight road from his home to a market 2.5 km away with a speed of 5kmph. Finding the market closed, he instantly turns and walks back home with a speed of 7.5kmph. The average speed of the man over the interval of time 0 to 40min is equal to? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A man walks on a straight road from his home to a market 2.5 km away with a speed of 5kmph. Finding the market closed, he instantly turns and walks back home with a speed of 7.5kmph. The average speed of the man over the interval of time 0 to 40min is equal to?.
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