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A solution containing a group-IV cation gives a precipitate on passing H2S. A solution of this precipitate in dil.HCl produces a white precipitate with NaOH solution and bluish-white precipitate with basic potassium ferrocyanide. The cation is :
- a)Co2+
- b)Ni2+
- c)Mn2+
- d)Zn2+
Correct answer is option 'C'. Can you explain this answer?
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A solution containing a group-IV cation gives a precipitate on passing...
Identification of the Cation
To determine the cation in the solution, we analyze the provided information step by step.
Precipitation with H2S
- A solution containing a group-IV cation gives a precipitate when H2S is passed.
- Group-IV cations typically include Sn2+, Pb2+, and others, but here we focus on the transition metals.
Reaction with Dilute HCl
- The precipitate formed is treated with dilute HCl, resulting in a white precipitate with NaOH.
- This indicates the formation of a hydroxide, which suggests that the cation could be Zn2+, considering its known reactions.
Basic Potassium Ferrocyanide Test
- The bluish-white precipitate formed with basic potassium ferrocyanide confirms the presence of Zn2+.
- When Zn2+ reacts with potassium ferrocyanide, it forms zinc ferrocyanide, which is bluish-white.
Exclusion of Other Options
- Co2+ typically produces a blue precipitate, not bluish-white.
- Ni2+ would form a green precipitate with NaOH and no significant response with ferrocyanide.
- Mn2+ usually does not produce a white precipitate with NaOH and has different ferrocyanide behavior.
Conclusion
- Based on the observations, the cation that meets all criteria is Zn2+.
- Thus, the correct answer is option 'C' - Zn2+.
This systematic analysis confirms the identity of the cation based on its chemical behavior and reaction products.
To determine the cation in the solution, we analyze the provided information step by step.
Precipitation with H2S
- A solution containing a group-IV cation gives a precipitate when H2S is passed.
- Group-IV cations typically include Sn2+, Pb2+, and others, but here we focus on the transition metals.
Reaction with Dilute HCl
- The precipitate formed is treated with dilute HCl, resulting in a white precipitate with NaOH.
- This indicates the formation of a hydroxide, which suggests that the cation could be Zn2+, considering its known reactions.
Basic Potassium Ferrocyanide Test
- The bluish-white precipitate formed with basic potassium ferrocyanide confirms the presence of Zn2+.
- When Zn2+ reacts with potassium ferrocyanide, it forms zinc ferrocyanide, which is bluish-white.
Exclusion of Other Options
- Co2+ typically produces a blue precipitate, not bluish-white.
- Ni2+ would form a green precipitate with NaOH and no significant response with ferrocyanide.
- Mn2+ usually does not produce a white precipitate with NaOH and has different ferrocyanide behavior.
Conclusion
- Based on the observations, the cation that meets all criteria is Zn2+.
- Thus, the correct answer is option 'C' - Zn2+.
This systematic analysis confirms the identity of the cation based on its chemical behavior and reaction products.
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A solution containing a group-IV cation gives a precipitate on passing H2S. A solution of this precipitate in dil.HCl produces a white precipitate with NaOH solution and bluish-white precipitate with basic potassium ferrocyanide. The cation is :a)Co2+b)Ni2+c)Mn2+d)Zn2+Correct answer is option 'C'. Can you explain this answer?
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