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Hydrolysis of sucrose is given by the following reaction.
Sucrose + H2O  ⇌ Glucose + Fructose
If the equilibrium constant (Kc) is 2 × 1013 at 300 K, the value of ΔrGº at the same temperature will be:
  • a)
    8.314 J mol–1 K–1 × 300 K × ln(3 × 1013)
  • b)
    –8.314 J mol–1 K–1 × 300 K × ln(4 × 1013)
  • c)
    –8.314 J mol–1 K–1 × 300 K × ln(2 × 1013)
  • d)
    8.314 J mol–1 K–1 × 300 K × ln(2 × 1013)
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Hydrolysis of sucrose is given by the following reaction.Sucrose + H2O...
ΔG°= -RT ln K
⇒ ΔG° = -8.314 J mol-1 K-1 × 300 K × ln (2 × 1013)
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Most Upvoted Answer
Hydrolysis of sucrose is given by the following reaction.Sucrose + H2O...
The equilibrium constant (Kc) for the hydrolysis of sucrose can be written as:

Kc = [Glucose] / [Fructose]

Since the reaction is given as:

Sucrose + H2O ↔ Glucose + Fructose

The equilibrium constant can also be written as:

Kc = ([Glucose] * [H2O]) / ([Sucrose] * [Fructose])

However, the concentration of water (H2O) is usually considered to be constant and does not appear in the equilibrium expression. Therefore, the equilibrium constant can be simplified to:

Kc = [Glucose] / [Sucrose]

Given that Kc is 2, it means that at equilibrium, the concentration of glucose is twice the concentration of sucrose.
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Hydrolysis of sucrose is given by the following reaction.Sucrose + H2OGlucose + FructoseIf the equilibrium constant (Kc) is 2 × 1013 at 300 K, the value of ΔrGº at the same temperature will be:a)8.314 J mol–1 K–1 × 300 K × ln(3 × 1013)b)–8.314 J mol–1 K–1 × 300 K × ln(4 × 1013)c)–8.314 J mol–1 K–1 × 300 K × ln(2 × 1013)d)8.314 J mol–1 K–1 × 300 K × ln(2 × 1013)Correct answer is option 'C'. Can you explain this answer?
Question Description
Hydrolysis of sucrose is given by the following reaction.Sucrose + H2OGlucose + FructoseIf the equilibrium constant (Kc) is 2 × 1013 at 300 K, the value of ΔrGº at the same temperature will be:a)8.314 J mol–1 K–1 × 300 K × ln(3 × 1013)b)–8.314 J mol–1 K–1 × 300 K × ln(4 × 1013)c)–8.314 J mol–1 K–1 × 300 K × ln(2 × 1013)d)8.314 J mol–1 K–1 × 300 K × ln(2 × 1013)Correct answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Hydrolysis of sucrose is given by the following reaction.Sucrose + H2OGlucose + FructoseIf the equilibrium constant (Kc) is 2 × 1013 at 300 K, the value of ΔrGº at the same temperature will be:a)8.314 J mol–1 K–1 × 300 K × ln(3 × 1013)b)–8.314 J mol–1 K–1 × 300 K × ln(4 × 1013)c)–8.314 J mol–1 K–1 × 300 K × ln(2 × 1013)d)8.314 J mol–1 K–1 × 300 K × ln(2 × 1013)Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Hydrolysis of sucrose is given by the following reaction.Sucrose + H2OGlucose + FructoseIf the equilibrium constant (Kc) is 2 × 1013 at 300 K, the value of ΔrGº at the same temperature will be:a)8.314 J mol–1 K–1 × 300 K × ln(3 × 1013)b)–8.314 J mol–1 K–1 × 300 K × ln(4 × 1013)c)–8.314 J mol–1 K–1 × 300 K × ln(2 × 1013)d)8.314 J mol–1 K–1 × 300 K × ln(2 × 1013)Correct answer is option 'C'. Can you explain this answer?.
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Here you can find the meaning of Hydrolysis of sucrose is given by the following reaction.Sucrose + H2OGlucose + FructoseIf the equilibrium constant (Kc) is 2 × 1013 at 300 K, the value of ΔrGº at the same temperature will be:a)8.314 J mol–1 K–1 × 300 K × ln(3 × 1013)b)–8.314 J mol–1 K–1 × 300 K × ln(4 × 1013)c)–8.314 J mol–1 K–1 × 300 K × ln(2 × 1013)d)8.314 J mol–1 K–1 × 300 K × ln(2 × 1013)Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Hydrolysis of sucrose is given by the following reaction.Sucrose + H2OGlucose + FructoseIf the equilibrium constant (Kc) is 2 × 1013 at 300 K, the value of ΔrGº at the same temperature will be:a)8.314 J mol–1 K–1 × 300 K × ln(3 × 1013)b)–8.314 J mol–1 K–1 × 300 K × ln(4 × 1013)c)–8.314 J mol–1 K–1 × 300 K × ln(2 × 1013)d)8.314 J mol–1 K–1 × 300 K × ln(2 × 1013)Correct answer is option 'C'. Can you explain this answer?, a detailed solution for Hydrolysis of sucrose is given by the following reaction.Sucrose + H2OGlucose + FructoseIf the equilibrium constant (Kc) is 2 × 1013 at 300 K, the value of ΔrGº at the same temperature will be:a)8.314 J mol–1 K–1 × 300 K × ln(3 × 1013)b)–8.314 J mol–1 K–1 × 300 K × ln(4 × 1013)c)–8.314 J mol–1 K–1 × 300 K × ln(2 × 1013)d)8.314 J mol–1 K–1 × 300 K × ln(2 × 1013)Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of Hydrolysis of sucrose is given by the following reaction.Sucrose + H2OGlucose + FructoseIf the equilibrium constant (Kc) is 2 × 1013 at 300 K, the value of ΔrGº at the same temperature will be:a)8.314 J mol–1 K–1 × 300 K × ln(3 × 1013)b)–8.314 J mol–1 K–1 × 300 K × ln(4 × 1013)c)–8.314 J mol–1 K–1 × 300 K × ln(2 × 1013)d)8.314 J mol–1 K–1 × 300 K × ln(2 × 1013)Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Hydrolysis of sucrose is given by the following reaction.Sucrose + H2OGlucose + FructoseIf the equilibrium constant (Kc) is 2 × 1013 at 300 K, the value of ΔrGº at the same temperature will be:a)8.314 J mol–1 K–1 × 300 K × ln(3 × 1013)b)–8.314 J mol–1 K–1 × 300 K × ln(4 × 1013)c)–8.314 J mol–1 K–1 × 300 K × ln(2 × 1013)d)8.314 J mol–1 K–1 × 300 K × ln(2 × 1013)Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice NEET tests.
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