The Laplace transform of unity function isa)1b)zeroc)sd)1/sCorrect ans...
The Laplace transform of the unity function is 1/s.
The unity function, also known as the step function or the Heaviside function, is defined as:
u(t) = 1, t >= 0
u(t) = 0, t < />
The Laplace transform is a mathematical tool used to transform a function of time, f(t), into a function of the complex variable s. It is defined as:
F(s) = L{f(t)} = ∫[0 to ∞] e^(-st) * f(t) dt
where s is a complex number parameter and F(s) is the Laplace transform of f(t).
To find the Laplace transform of the unity function, we substitute u(t) into the Laplace transform equation:
F(s) = L{u(t)} = ∫[0 to ∞] e^(-st) * u(t) dt
Since the unity function is equal to 1 for t >= 0, the integral becomes:
F(s) = ∫[0 to ∞] e^(-st) dt
Integrating the exponential function with respect to t gives:
F(s) = [-1/s * e^(-st)] [0 to ∞]
Applying the limits of integration:
F(s) = [-1/s * e^(-s∞)] - [-1/s * e^(-s0)]
As t approaches infinity, e^(-s∞) approaches zero. Also, e^(-s0) is equal to 1. Therefore, the equation simplifies to:
F(s) = 0 - (-1/s)
F(s) = 1/s
Thus, the Laplace transform of the unity function is 1/s.
Therefore, the correct answer is option 'D'.