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A series RLC circuit consist of resistance of 10 ohms, an inductance of 0.1 H and a capacitance of 0.001 \xf. The frequency at resonance is
- a)105 Hz
- b)15920 Hz
- c)107 Hz
- d)920 Hz
Correct answer is option 'B'. Can you explain this answer?
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Resonance Frequency Calculation:
To determine the resonance frequency of the RLC circuit, we can use the formula:
f = 1 / (2 * π * √(LC))
Given values:
- Resistance (R) = 10 ohms
- Inductance (L) = 0.1 H
- Capacitance (C) = 0.001 μF = 0.001 * 10^(-6) F
Calculations:
- Convert capacitance from μF to F: 0.001 μF = 0.001 * 10^(-6) F = 1 * 10^(-9) F
- Substitute the values into the formula:
f = 1 / (2 * π * √(0.1 * 1 * 10^(-9)))
f = 1 / (2 * π * √(1 * 10^(-10)))
f = 1 / (2 * π * 10^(-5))
f = 1 / (2 * 3.14159 * 10^(-5))
f ≈ 15920 Hz
Therefore, the resonance frequency of the RLC circuit is approximately 15920 Hz, which corresponds to option 'B'.
To determine the resonance frequency of the RLC circuit, we can use the formula:
f = 1 / (2 * π * √(LC))
Given values:
- Resistance (R) = 10 ohms
- Inductance (L) = 0.1 H
- Capacitance (C) = 0.001 μF = 0.001 * 10^(-6) F
Calculations:
- Convert capacitance from μF to F: 0.001 μF = 0.001 * 10^(-6) F = 1 * 10^(-9) F
- Substitute the values into the formula:
f = 1 / (2 * π * √(0.1 * 1 * 10^(-9)))
f = 1 / (2 * π * √(1 * 10^(-10)))
f = 1 / (2 * π * 10^(-5))
f = 1 / (2 * 3.14159 * 10^(-5))
f ≈ 15920 Hz
Therefore, the resonance frequency of the RLC circuit is approximately 15920 Hz, which corresponds to option 'B'.
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A series RLC circuit consist of resistance of 10 ohms, an inductance of 0.1 H and a capacitance of 0.001 \xf. The frequency at resonance isa)105 Hz b)15920 Hzc)107 Hz d)920 HzCorrect answer is option 'B'. Can you explain this answer?
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