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If NaCl is dopped with 10^-3 mol% of SrCl2 what is the concentration of cation vacancies?
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If NaCl is dopped with 10^-3 mol% of SrCl2 what is the concentration o...
NaCl is doped with 10-³ mol % of SrCl2.
100 moles of NaCl are doped with 0.001 moles of SrCl2.
1 mole of NaCl is doped with 0.001/100=10−^5 moles of SrCl2 or 10^5moles of Sr2+ cations.
One Sr2+ ion creates one cation vacancy.
10−^5 moles of Sr2+ will create 10−^5 moles of cation vacancies which correspond to 10-^5×6.023×10²³=6.023×10^18cation vacancies per mole of NaCl.
100 moles of NaCl are doped with 0.001 moles of SrCl2.
1 mole of NaCl is doped with 0.001/100=10−^5 moles of SrCl2 or 10^5moles of Sr2+ cations.
One Sr2+ ion creates one cation vacancy.
10−^5 moles of Sr2+ will create 10−^5 moles of cation vacancies which correspond to 10-^5×6.023×10²³=6.023×10^18cation vacancies per mole of NaCl.
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If NaCl is dopped with 10^-3 mol% of SrCl2 what is the concentration o...
Calculation of Cation Vacancy Concentration in NaCl doped with SrCl2
NaCl being doped with 10^-3 mol% of SrCl2 will introduce cation vacancies in the crystal lattice due to the difference in ionic radii between Na+ and Sr2+ ions.
Step 1: Calculate the concentration of SrCl2
- Given that NaCl is doped with 10^-3 mol% of SrCl2
- This means that for every 10^6 molecules of NaCl, there are 1 molecule of SrCl2
- Therefore, the concentration of SrCl2 = 10^-3 mol% = 10^-5 mol
Step 2: Calculate the cation vacancies
- For every molecule of SrCl2 doped, one Na+ ion is replaced by Sr2+ ion
- This leads to the creation of one cation vacancy in the NaCl crystal lattice
- Therefore, the concentration of cation vacancies = concentration of SrCl2 = 10^-5 mol
Therefore, the concentration of cation vacancies in NaCl doped with 10^-3 mol% of SrCl2 is 10^-5 mol. This concentration of cation vacancies will affect the properties of the NaCl crystal, such as conductivity, mechanical strength, and optical properties.
NaCl being doped with 10^-3 mol% of SrCl2 will introduce cation vacancies in the crystal lattice due to the difference in ionic radii between Na+ and Sr2+ ions.
Step 1: Calculate the concentration of SrCl2
- Given that NaCl is doped with 10^-3 mol% of SrCl2
- This means that for every 10^6 molecules of NaCl, there are 1 molecule of SrCl2
- Therefore, the concentration of SrCl2 = 10^-3 mol% = 10^-5 mol
Step 2: Calculate the cation vacancies
- For every molecule of SrCl2 doped, one Na+ ion is replaced by Sr2+ ion
- This leads to the creation of one cation vacancy in the NaCl crystal lattice
- Therefore, the concentration of cation vacancies = concentration of SrCl2 = 10^-5 mol
Therefore, the concentration of cation vacancies in NaCl doped with 10^-3 mol% of SrCl2 is 10^-5 mol. This concentration of cation vacancies will affect the properties of the NaCl crystal, such as conductivity, mechanical strength, and optical properties.
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If NaCl is dopped with 10^-3 mol% of SrCl2 what is the concentration of cation vacancies?
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