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If NaCl is dopped with 10^-3 mol% of SrCl2 what is the concentration of cation vacancies?
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If NaCl is dopped with 10^-3 mol% of SrCl2 what is the concentration o...
NaCl is doped with 10-³ mol % of SrCl2.
100 moles of NaCl are doped with 0.001 moles of SrCl2.
1 mole of NaCl is doped with 0.001/100=10−^5 moles of SrCl2 or 10^5moles of Sr2+ cations.
One Sr2+ ion creates one cation vacancy.
10−^5 moles of Sr2+ will create 10−^5 moles of cation vacancies which correspond to 10-^5×6.023×10²³=6.023×10^18cation vacancies per mole of NaCl.
100 moles of NaCl are doped with 0.001 moles of SrCl2.
1 mole of NaCl is doped with 0.001/100=10−^5 moles of SrCl2 or 10^5moles of Sr2+ cations.
One Sr2+ ion creates one cation vacancy.
10−^5 moles of Sr2+ will create 10−^5 moles of cation vacancies which correspond to 10-^5×6.023×10²³=6.023×10^18cation vacancies per mole of NaCl.
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If NaCl is dopped with 10^-3 mol% of SrCl2 what is the concentration o...
Calculation of Cation Vacancy Concentration in NaCl doped with SrCl2
NaCl being doped with 10^-3 mol% of SrCl2 will introduce cation vacancies in the crystal lattice due to the difference in ionic radii between Na+ and Sr2+ ions.
Step 1: Calculate the concentration of SrCl2
- Given that NaCl is doped with 10^-3 mol% of SrCl2
- This means that for every 10^6 molecules of NaCl, there are 1 molecule of SrCl2
- Therefore, the concentration of SrCl2 = 10^-3 mol% = 10^-5 mol
Step 2: Calculate the cation vacancies
- For every molecule of SrCl2 doped, one Na+ ion is replaced by Sr2+ ion
- This leads to the creation of one cation vacancy in the NaCl crystal lattice
- Therefore, the concentration of cation vacancies = concentration of SrCl2 = 10^-5 mol
Therefore, the concentration of cation vacancies in NaCl doped with 10^-3 mol% of SrCl2 is 10^-5 mol. This concentration of cation vacancies will affect the properties of the NaCl crystal, such as conductivity, mechanical strength, and optical properties.
NaCl being doped with 10^-3 mol% of SrCl2 will introduce cation vacancies in the crystal lattice due to the difference in ionic radii between Na+ and Sr2+ ions.
Step 1: Calculate the concentration of SrCl2
- Given that NaCl is doped with 10^-3 mol% of SrCl2
- This means that for every 10^6 molecules of NaCl, there are 1 molecule of SrCl2
- Therefore, the concentration of SrCl2 = 10^-3 mol% = 10^-5 mol
Step 2: Calculate the cation vacancies
- For every molecule of SrCl2 doped, one Na+ ion is replaced by Sr2+ ion
- This leads to the creation of one cation vacancy in the NaCl crystal lattice
- Therefore, the concentration of cation vacancies = concentration of SrCl2 = 10^-5 mol
Therefore, the concentration of cation vacancies in NaCl doped with 10^-3 mol% of SrCl2 is 10^-5 mol. This concentration of cation vacancies will affect the properties of the NaCl crystal, such as conductivity, mechanical strength, and optical properties.
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If NaCl is dopped with 10^-3 mol% of SrCl2 what is the concentration of cation vacancies? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If NaCl is dopped with 10^-3 mol% of SrCl2 what is the concentration of cation vacancies? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If NaCl is dopped with 10^-3 mol% of SrCl2 what is the concentration of cation vacancies?.
If NaCl is dopped with 10^-3 mol% of SrCl2 what is the concentration of cation vacancies? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about If NaCl is dopped with 10^-3 mol% of SrCl2 what is the concentration of cation vacancies? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If NaCl is dopped with 10^-3 mol% of SrCl2 what is the concentration of cation vacancies?.
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