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Four resistances 80 Ω, 50 Ω, 25 Ω and R are connected in parallel. Current through 25 Ω resistance is 4 A. The total current of the supply is 10 A. The value of R will be
  • a)
    66.66 Ω    
  • b)
    36.36 Ω
  • c)
    40.25 Ω
  • d)
    76.56 Ω
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Four resistances 80 Ω, 50 Ω, 25 Ω and R are connecte...


Given, I25Ω=4 A
Here, R' = 80║50║R



or, 
or, 

or, 29R + 400 = 40R or 11R = 400
or, R = 36.36 Ω
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Most Upvoted Answer
Four resistances 80 Ω, 50 Ω, 25 Ω and R are connecte...
, 120, 160, and 200 ohms are connected in parallel. What is the equivalent resistance of the system?

To find the equivalent resistance of the parallel resistances, we use the formula:

1/R_total = 1/R1 + 1/R2 + 1/R3 + 1/R4

where R1, R2, R3, and R4 are the resistances in ohms.

Substituting the values given, we get:

1/R_total = 1/80 + 1/120 + 1/160 + 1/200

Simplifying, we get:

1/R_total = 0.015 + 0.0083 + 0.00625 + 0.005

1/R_total = 0.03455

Taking the reciprocal of both sides, we get:

R_total = 28.93 ohms

Therefore, the equivalent resistance of the system is approximately 28.93 ohms.
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Four resistances 80 Ω, 50 Ω, 25 Ω and R are connected in parallel. Current through 25 Ω resistance is 4 A. The total current of the supply is 10 A. The value of R will bea)66.66 Ω b)36.36 Ωc)40.25 Ωd)76.56 ΩCorrect answer is option 'B'. Can you explain this answer?
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