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Find the sum of the first 15 multiples of 8.
  • a)
    960
  • b)
    520
  • c)
    440
  • d)
    600
Correct answer is option 'A'. Can you explain this answer?
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The first step to finding the sum of the first 15 multiples of 8 is to list out the multiples.

Listing the multiples:
8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, 104, 112, 120

To find the sum, we can add up all the multiples.

Adding the multiples:
8 + 16 + 24 + 32 + 40 + 48 + 56 + 64 + 72 + 80 + 88 + 96 + 104 + 112 + 120 = 1200

So, the sum of the first 15 multiples of 8 is 1200.

However, none of the answer choices match the calculated sum of 1200.

To find the correct answer, we need to consider that we are only looking for the sum of the first 15 multiples of 8.

The sum of the first n multiples of a number can be found using the formula:
Sum = (n/2)(first term + last term)

In this case, the first term is 8 and the last term is 120.

Using the formula:
Sum = (15/2)(8 + 120) = (15/2)(128) = 15 * 64 = 960

Therefore, the correct answer is option A) 960.
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