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A object is moving with velocity v (with respect ground) parallel to plane mirror M1. Another plane mirror M2 makes an angle β with the vertical as shown. Then the velocity of image in mirror M2 with respect to the image in M1 is,



  • a)
    v sin β 

  • b)
    v cos 2β

  • c)
    2v sin β

  • d)
    v√2

Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A object is moving with velocity v (with respect ground) parallel to p...
we have to find magnitude of relative velocity between v1 and v2.The angle between these two vectors is

Hence vr=v1−v2
|vr|=|v1−v2|
This is nothing but magnitude of subtration of two velocity vectors of equal magnitudes v each and angle between them equal to 2β
Hence
∣vr∣ = √v+ v+ 2(v)(v)cos2θ 
Solving these two equations ,we get
∣v2∣ = 2v sinβ
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Most Upvoted Answer
A object is moving with velocity v (with respect ground) parallel to p...
we have to find magnitude of relative velocity between v1 and v2.The angle between these two vectors is

Hence vr=v1−v2
|vr|=|v1−v2|
This is nothing but magnitude of subtration of two velocity vectors of equal magnitudes v each and angle between them equal to 2β
Hence
∣vr∣ = √v+ v+ 2(v)(v)cos2θ 
Solving these two equations ,we get
∣v2∣ = 2v sinβ
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A object is moving with velocity v (with respect ground) parallel to plane mirror M1. Another plane mirror M2makes an angleβ with the vertical as shown. Then the velocity of image in mirror M2with respect to the image in M1is,a)v sinβb)v cos2βc)2v sinβd)v√2Correct answer is option 'C'. Can you explain this answer?
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