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The avarage of x no. Is calculated 36. It is later discovered that a no. 48 was mistakely read 84 while calculating the avarage if the correct avarage is35. 25 then find the value of x.?
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The avarage of x no. Is calculated 36. It is later discovered that a n...
Question: The average of x numbers is calculated as 36. It is later discovered that a number 48 was mistakenly read as 84 while calculating the average. If the correct average is 35.25, then find the value of x?

Solution:

Let's first find the sum of x numbers using the given average.
Sum of x numbers = Average * Number of terms = 36 * x

Now, we know that a number 48 was mistakenly read as 84. So, the difference between the correct sum and the sum calculated earlier is (84 - 48) = 36.

Correct sum of x numbers = 36 * x + 36

We also know that the correct average is 35.25. So, we can write:

Correct sum of x numbers / Number of terms = 35.25

Substituting the value of correct sum, we get:

(36 * x + 36) / x = 35.25

Multiplying both sides by x, we get:

36 * x + 36 = 35.25 * x

Simplifying, we get:

0.75 * x = 36

x = 48

Therefore, the value of x is 48.

Answer: The value of x is 48.
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The avarage of x no. Is calculated 36. It is later discovered that a n...
36.25
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The avarage of x no. Is calculated 36. It is later discovered that a no. 48 was mistakely read 84 while calculating the avarage if the correct avarage is35. 25 then find the value of x.?
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