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marbles of diameter 1.4 cm are dropped into a cylindrical vessel of diameter 7 cm containing sone water find the number of marbles drop so that the water lavel rises by 5.6cm
Most Upvoted Answer
?marbles of diameter 1.4 cm are dropped into a cylindrical vessel of d...
Solution :

Diameter of the Spherical ball ( d ) = 1.4cm

radius of the ball ( r ) = d/2

r = 0.7 cm

Volume of the Sphere = ( 4/3 )πr³ cm³

v = ( 4/3 ) π ( 0.7 )³ ----( 1 )

ii ) Diameter of the cylinder ( D ) = 7cm

radius of the cylinder ( R ) = D/2

R = 7/2 cm

Suppose water level rises by h= 5.6 cm

in the cylindrical beacker .

Then ,

Volume of the cylinder of height

h = 5.6 cm and radius 7/2 cm

V = πR²h

V = [ π ×( 7/2 )² × 5.6 ]cm³ ----( 2 )

Let the number of balls dropped in the

beaker = n

n = V /v

n = [π ×(7/2)²×5.6cm³]/ [4/3×π×(0.7)³cm³]

after cancellation ,we get

n = 150
Community Answer
?marbles of diameter 1.4 cm are dropped into a cylindrical vessel of d...
The answer will be approx 150 marbles.
Here, we see in this question,, there is a cylindrical vessel and spherical marbles...
so, we have,,
• volume of cylindrical vessel =πr²h. (π=22/7)
radius(r)=7/2=3.5cm, height(h)=5.6cm.
•volume of spherical marble =4/3πr³(r=14/2=0.7cm)
therefore, the no. of marbles =the volume of cylindrical vessel /the volume of spherical marble
=(22/7* 3.5 * 3.5 * 5.6 )÷ (4/3 * 22/7 * 14/2 * 14/2 * 14.2) =approx 150 marble.
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?marbles of diameter 1.4 cm are dropped into a cylindrical vessel of diameter 7 cm containing sone water find the number of marbles drop so that the water lavel rises by 5.6cm
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