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A bag contains 5 red balls and n green balls. If the probability of drawing a green ball is three times that of a red ball, then find the value of n.?
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A bag contains 5 red balls and n green balls. If the probability of dr...
Solution:

Let the total number of balls in the bag be x.

Given, there are 5 red balls and n green balls.

Probability of drawing a red ball = 5/x

Probability of drawing a green ball = n/x

Given, probability of drawing a green ball is three times that of a red ball.

So, (n/x) = 3*(5/x)

Simplifying it, we get n = 15

Therefore, the value of n is 15.

Explanation:

The question is based on probability. We are given a bag that contains 5 red balls and n green balls. We need to find the value of n when the probability of drawing a green ball is three times that of a red ball.

We start by using probability formulas. Probability is the likelihood of an event occurring. It can be expressed as a fraction, decimal or percentage.

Let the total number of balls in the bag be x. Therefore, the probability of drawing a red ball is 5/x and the probability of drawing a green ball is n/x.

Given, probability of drawing a green ball is three times that of a red ball. So, we can express it as:

(n/x) = 3*(5/x)

Simplifying it, we get n = 15.

Therefore, the value of n is 15.

Hence, we can conclude that the bag contains 5 red balls and 15 green balls.
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A bag contains 5 red balls and n green balls. If the probability of dr...
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A bag contains 5 red balls and n green balls. If the probability of drawing a green ball is three times that of a red ball, then find the value of n.?
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