The reaction Pb(NO3)2 + 2NaI → 2NaNO3 + PbI2 ↓ is classified asa)Combi...
In this reaction, two new substances lead iodide, and sodium nitrate are formed by an interchange of radicals in lead nitrate and sodium iodide.
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The reaction Pb(NO3)2 + 2NaI → 2NaNO3 + PbI2 ↓ is classified asa)Combi...
**Double Replacement Reaction**
A double replacement reaction, also known as a double displacement or metathesis reaction, is a type of chemical reaction where two compounds exchange ions to form new compounds. In this reaction, the cations and anions of two different compounds switch places, resulting in the formation of two new compounds.
**Explanation:**
Let's analyze the given reaction:
Pb(NO3)2 + 2NaI → 2NaNO3 + PbI2 ↓
- **Pb(NO3)2**: This is lead(II) nitrate, which is composed of the lead ion (Pb^2+) and the nitrate ion (NO3^-).
- **2NaI**: This is sodium iodide, which is composed of the sodium ion (Na^+) and the iodide ion (I^-).
When these two compounds react, the following exchange of ions takes place:
- The lead ion (Pb^2+) from lead(II) nitrate combines with the iodide ion (I^-) from sodium iodide to form lead(II) iodide (PbI2). This is represented by the precipitation symbol (↓), indicating the formation of a solid product.
- The sodium ion (Na^+) from sodium iodide combines with the nitrate ion (NO3^-) from lead(II) nitrate to form sodium nitrate (NaNO3).
Therefore, the reaction can be written as:
Pb(NO3)2 + 2NaI → 2NaNO3 + PbI2 ↓
Since the cations and anions of two different compounds have exchanged places to form new compounds, this reaction is classified as a **double replacement** reaction.
The reaction Pb(NO3)2 + 2NaI → 2NaNO3 + PbI2 ↓ is classified asa)Combi...
The exchange of ions between two compounds will lead to a double displacement reaction