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A spindle 5 cm in diameter turns 110 revolutions per minute in a bearing 5.004 cm internal diameter. The intervening space is filled to 20 cm depth with a lubricating oil of dynamic viscosity 0.08 Pa‑s. If the oil pressure is 4000 kPa, make calculations for the oil leakage along the spindle and the resisting torque due to viscous drag of the oil film.a) 2.61 × 10−8 m3/s and 0.875 Nmb) 0.875 m3/s and 2.61 Nmc) 3.71 × 10−8 m3/s and 0.087 Nm (d)2.61 × 10−6 m3/s and 8.75 NmCorrect answer is option 'A'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A spindle 5 cm in diameter turns 110 revolutions per minute in a bearing 5.004 cm internal diameter. The intervening space is filled to 20 cm depth with a lubricating oil of dynamic viscosity 0.08 Pa‑s. If the oil pressure is 4000 kPa, make calculations for the oil leakage along the spindle and the resisting torque due to viscous drag of the oil film.a) 2.61 × 10−8 m3/s and 0.875 Nmb) 0.875 m3/s and 2.61 Nmc) 3.71 × 10−8 m3/s and 0.087 Nm (d)2.61 × 10−6 m3/s and 8.75 NmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A spindle 5 cm in diameter turns 110 revolutions per minute in a bearing 5.004 cm internal diameter. The intervening space is filled to 20 cm depth with a lubricating oil of dynamic viscosity 0.08 Pa‑s. If the oil pressure is 4000 kPa, make calculations for the oil leakage along the spindle and the resisting torque due to viscous drag of the oil film.a) 2.61 × 10−8 m3/s and 0.875 Nmb) 0.875 m3/s and 2.61 Nmc) 3.71 × 10−8 m3/s and 0.087 Nm (d)2.61 × 10−6 m3/s and 8.75 NmCorrect answer is option 'A'. Can you explain this answer?.

Solutions for A spindle 5 cm in diameter turns 110 revolutions per minute in a bearing 5.004 cm internal diameter. The intervening space is filled to 20 cm depth with a lubricating oil of dynamic viscosity 0.08 Pa‑s. If the oil pressure is 4000 kPa, make calculations for the oil leakage along the spindle and the resisting torque due to viscous drag of the oil film.a) 2.61 × 10−8 m3/s and 0.875 Nmb) 0.875 m3/s and 2.61 Nmc) 3.71 × 10−8 m3/s and 0.087 Nm (d)2.61 × 10−6 m3/s and 8.75 NmCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Civil Engineering (CE). Download more important topics, notes, lectures and mock test series for Civil Engineering (CE) Exam by signing up for free.

Here you can find the meaning of A spindle 5 cm in diameter turns 110 revolutions per minute in a bearing 5.004 cm internal diameter. The intervening space is filled to 20 cm depth with a lubricating oil of dynamic viscosity 0.08 Pa‑s. If the oil pressure is 4000 kPa, make calculations for the oil leakage along the spindle and the resisting torque due to viscous drag of the oil film.a) 2.61 × 10−8 m3/s and 0.875 Nmb) 0.875 m3/s and 2.61 Nmc) 3.71 × 10−8 m3/s and 0.087 Nm (d)2.61 × 10−6 m3/s and 8.75 NmCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A spindle 5 cm in diameter turns 110 revolutions per minute in a bearing 5.004 cm internal diameter. The intervening space is filled to 20 cm depth with a lubricating oil of dynamic viscosity 0.08 Pa‑s. If the oil pressure is 4000 kPa, make calculations for the oil leakage along the spindle and the resisting torque due to viscous drag of the oil film.a) 2.61 × 10−8 m3/s and 0.875 Nmb) 0.875 m3/s and 2.61 Nmc) 3.71 × 10−8 m3/s and 0.087 Nm (d)2.61 × 10−6 m3/s and 8.75 NmCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for A spindle 5 cm in diameter turns 110 revolutions per minute in a bearing 5.004 cm internal diameter. The intervening space is filled to 20 cm depth with a lubricating oil of dynamic viscosity 0.08 Pa‑s. If the oil pressure is 4000 kPa, make calculations for the oil leakage along the spindle and the resisting torque due to viscous drag of the oil film.a) 2.61 × 10−8 m3/s and 0.875 Nmb) 0.875 m3/s and 2.61 Nmc) 3.71 × 10−8 m3/s and 0.087 Nm (d)2.61 × 10−6 m3/s and 8.75 NmCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of A spindle 5 cm in diameter turns 110 revolutions per minute in a bearing 5.004 cm internal diameter. The intervening space is filled to 20 cm depth with a lubricating oil of dynamic viscosity 0.08 Pa‑s. If the oil pressure is 4000 kPa, make calculations for the oil leakage along the spindle and the resisting torque due to viscous drag of the oil film.a) 2.61 × 10−8 m3/s and 0.875 Nmb) 0.875 m3/s and 2.61 Nmc) 3.71 × 10−8 m3/s and 0.087 Nm (d)2.61 × 10−6 m3/s and 8.75 NmCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A spindle 5 cm in diameter turns 110 revolutions per minute in a bearing 5.004 cm internal diameter. The intervening space is filled to 20 cm depth with a lubricating oil of dynamic viscosity 0.08 Pa‑s. If the oil pressure is 4000 kPa, make calculations for the oil leakage along the spindle and the resisting torque due to viscous drag of the oil film.a) 2.61 × 10−8 m3/s and 0.875 Nmb) 0.875 m3/s and 2.61 Nmc) 3.71 × 10−8 m3/s and 0.087 Nm (d)2.61 × 10−6 m3/s and 8.75 NmCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice Civil Engineering (CE) tests.