In a double-pipe heat exchanger, the cold fluid is water with inlet te...
For parallel flow heat exchanger maximum temperature of cold fluid will be reached when both hot and cold fluid exit at the same temperature.
Thus by steady state flow energy equation
⇒ 20 x 4.2 x (T - 20) = 10 x 4.2 (80-T)
∴ T = 40oC
For counter flow heat exchanger, maximum exit temperature of cold fluid is achieved when effectiveness of the heat exchanger is 1
i.e.
ε = 1
i.e.
(mccpc)(Tco - Tci)/(mccpc)(Thi - Tci) =1
1 = 20 x 4.2 x [T - 20]/10 x 4.2 x [80 - 20]
T = 50oC
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In a double-pipe heat exchanger, the cold fluid is water with inlet te...
Given:
Cold fluid temperature, T1 = 20°C
Hot fluid temperature, T2 = 80°C
Mass flow rate of cold fluid, m1 = 20 kg/s
Mass flow rate of hot fluid, m2 = 10 kg/s
Specific heat of water, cp = 4.2 kJ/kg°C
To find:
Maximum temperature to which the cold fluid can be heated in a parallel flow and in a counter flow heat exchanger
Solution:
The maximum temperature to which the cold fluid can be heated in a heat exchanger depends on the effectiveness of the heat exchanger. The effectiveness of the heat exchanger depends on the flow arrangement of the fluids.
Parallel flow heat exchanger:
In a parallel flow heat exchanger, the hot and cold fluids flow in the same direction. The effectiveness of the parallel flow heat exchanger is given by:
ε = (T2 - T1)/(T2 - T1') ----(1)
where T1' is the outlet temperature of the cold fluid.
The maximum temperature to which the cold fluid can be heated in a parallel flow heat exchanger is obtained by setting ε = 1 in equation (1) and solving for T1':
1 = (T2 - T1)/(T2 - T1')
T1' = T2 - (T2 - T1)/1
T1' = 2T2 - T1
T1' = 2(80) - 20
T1' = 140°C
Therefore, the maximum temperature to which the cold fluid can be heated in a parallel flow heat exchanger is 140°C.
Counter flow heat exchanger:
In a counter flow heat exchanger, the hot and cold fluids flow in opposite directions. The effectiveness of the counter flow heat exchanger is given by:
ε = (T2 - T1)/(T2 - T1') * ln[(T2 - T1)/(T2 - T1')] / ln[(T2 - T1)/(T2 - T1'')] ----(2)
where T1'' is the outlet temperature of the hot fluid.
The maximum temperature to which the cold fluid can be heated in a counter flow heat exchanger is obtained by setting ε = 1 in equation (2) and solving for T1':
1 = (T2 - T1)/(T2 - T1') * ln[(T2 - T1)/(T2 - T1')] / ln[(T2 - T1)/(T2 - T1'')]
T1' = T2 - (T2 - T1)/[(1)(ln[(T2 - T1)/(T2 - T1')]/ln[(T2 - T1)/(T2 - T1'')])]
T1' = T2 - (T2 - T1)/(ln[(T2 - T1)/(T2 - T1'')]/ln[(T2 - T1)/(T2 - T1')])
T1' = T2 - (T2 - T1)/(ln[(T2 - T1)/(T2 - T1'')]/ln[(T2 - T1)/(T2 - T1')])
T1' = 2T2 - T1
T1' = 2(80) - 20
T1' = 140°C
Therefore, the maximum temperature to which the cold fluid