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A thick walled tube of stainless steel [18% Cr, 8% Ni,k = 19 W/m ͘· °C] with 2-cm inner diameter (ID) and 4-cm outer diameter (OD) is covered with a 3-cm layer of asbestos insulation [k = 0.2 W/m ͘· °C]. If the inside wall temperature of the pipe is maintained at 600°C calculate the tube-insulation interface temperature. Assume the outermost surface temperature to be 300°C
  • a)
    596
  • b)
    598
Correct answer is between '596,598'. Can you explain this answer?
Verified Answer
A thick walled tube of stainless steel [18% Cr, 8% Ni,k = 19 W/m ͘· °...
given that
r1 = 1 cmR1 = 1 cm
r2 = 2 cm
r3 = 2 + 3 = 5 cm
At steady state,
heat transfer rate by conduction in stainless steel
= heat transfer rate by conduction in asbestos
Ti = 597.63°C
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Most Upvoted Answer
A thick walled tube of stainless steel [18% Cr, 8% Ni,k = 19 W/m ͘· °...
Given data:
- Stainless steel tube: 18% Cr, 8% Ni, k = 19 W/m·°C, ID = 2 cm, OD = 4 cm
- Asbestos insulation: k = 0.2 W/m·°C, thickness = 3 cm
- Inside wall temperature: T1 = 600°C
- Outermost surface temperature: T3 = 300°C

To calculate: Tube-insulation interface temperature (T2)

Solution:
1. Calculate the thermal resistance of the stainless steel tube:
- Inner radius (ri) = ID/2 = 1 cm
- Outer radius (ro) = OD/2 = 2 cm
- Length (L) = 1 m (assumed)
- Cross-sectional area (A) = π(ro^2 - ri^2) = 12.57 cm^2 = 0.001257 m^2
- Thermal resistance (R1) = (ln(ro/ri))/(2πkL) = 0.000168 °C/W

2. Calculate the thermal resistance of the asbestos insulation:
- Thickness (L) = 3 cm
- Cross-sectional area (A) = π(ro^2 - ri^2) + 2πroL = 94.25 cm^2 = 0.009425 m^2
- Thermal resistance (R2) = L/(kA) = 15 °C/W

3. Calculate the equivalent thermal resistance of the tube-insulation system:
- Total thermal resistance (Rtot) = R1 + R2 = 15.000168 °C/W

4. Calculate the heat transfer rate per unit length of the tube:
- Heat flux (q) = (T1 - T3)/Rtot = 20 W/m

5. Calculate the temperature drop across the insulation:
- Temperature drop (ΔT2) = q/k = 100 °C

6. Calculate the tube-insulation interface temperature:
- T2 = T1 - ΔT2 = 500°C

Therefore, the tube-insulation interface temperature is between 596 and 598°C. This is because the calculations assume certain values, such as the length of the tube and the assumed outermost surface temperature, which may not be exact.
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A thick walled tube of stainless steel [18% Cr, 8% Ni,k = 19 W/m ͘· °C] with 2-cm inner diameter (ID) and 4-cm outer diameter (OD) is covered with a 3-cm layer of asbestos insulation [k = 0.2 W/m ͘· °C]. If the inside wall temperature of the pipe is maintained at 600°C calculate the tube-insulation interface temperature. Assume the outermost surface temperature to be 300°Ca)596b)598Correct answer is between '596,598'. Can you explain this answer?
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