The sum of the digits of a two-digit number is 11. If 45 is added to ...
The given problem can be solved by using algebraic equations. Let's break down the problem into smaller steps:Step 1: Understanding the first statement
The sum of the digits of a two-digit number is 11. Let's assume the two-digit number as '10x + y', where x represents the tens digit and y represents the units digit. So we have the equation:
x + y = 11
Step 2: Understanding the second statement
If 45 is added to the number, the digits are reversed. This means that the new number would be '10y + x'. So we have the equation:
(10x + y) + 45 = 10y + x
Step 3: Simplifying the equation
Let's simplify the equation by combining like terms:
10x + y + 45 = 10y + x
Simplifying further:
9x - 9y = 45
Dividing both sides of the equation by 9:
x - y = 5
Step 4: Solving the equations
We now have a system of equations:
x + y = 11
x - y = 5
Adding the two equations together, we get:
2x = 16
Dividing both sides by 2, we find that x = 8.
Substituting the value of x in the first equation, we can find y:
8 + y = 11
Simplifying further, we find that y = 3.
Step 5: Finding the number
Now that we have the values of x and y, we can determine the two-digit number:
10x + y = 10(8) + 3 = 80 + 3 = 83
Therefore, the number is 83.
Conclusion:The two-digit number in this problem is 83. Therefore, the correct answer is option C) 38.