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Two infinitely large parallel plates 1 & 2, facing each other are separated by a very small gap. The plates are exchanging heat by thermal radiation and gap between them is filled with non-participating medium. Surface 1 is a black surface with temperature equal to and surface 2 is a grey surface with temperature equal to and emissivity equal to 0.8. Find out the radiosity for surface 2 in kW/m2
  • a)
    6.76
  • b)
    6.80
  • c)
    6.81
  • d)
    6.91
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Two infinitely large parallel plates 1 & 2, facing each other are ...
Consider radiation heat exchange between the surface as shown.
Black Grey,ε2 = 0.8
T1 = 800 K T2 = 500 K
Therefore radiosity for surface 2 is given as
J2 = E2 + ρ2E1
J2 = E2 + (1-α2)E1
By Kirchoff’s law, α2 = ε2
∴ J2 = (1-ε2)E1+ E2
As ① is a black surface,
E1 = σT14
and ② is a gray surface,
E2 = ε2σT24
∴ J2 = (1-ε2)σT14 + ε2σT24
J2 = σ[(1-ε)T14 + ε2T24]
J2 = 5.67 x 10-8 + [(1-0.8) x 8004 + 0.6 x 5004]
J2 = 6.77 kW/m2
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Most Upvoted Answer
Two infinitely large parallel plates 1 & 2, facing each other are ...
Consider radiation heat exchange between the surface as shown.
Black Grey,ε2 = 0.8
T1 = 800 K T2 = 500 K
Therefore radiosity for surface 2 is given as
J2 = E2 + ρ2E1
J2 = E2 + (1-α2)E1
By Kirchoff’s law, α2 = ε2
∴ J2 = (1-ε2)E1+ E2
As ① is a black surface,
E1 = σT14
and ② is a gray surface,
E2 = ε2σT24
∴ J2 = (1-ε2)σT14 + ε2σT24
J2 = σ[(1-ε)T14 + ε2T24]
J2 = 5.67 x 10-8 + [(1-0.8) x 8004 + 0.6 x 5004]
J2 = 6.77 kW/m2
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Community Answer
Two infinitely large parallel plates 1 & 2, facing each other are ...
Consider radiation heat exchange between the surface as shown.
Black Grey,ε2 = 0.8
T1 = 800 K T2 = 500 K
Therefore radiosity for surface 2 is given as
J2 = E2 + ρ2E1
J2 = E2 + (1-α2)E1
By Kirchoff’s law, α2 = ε2
∴ J2 = (1-ε2)E1+ E2
As ① is a black surface,
E1 = σT14
and ② is a gray surface,
E2 = ε2σT24
∴ J2 = (1-ε2)σT14 + ε2σT24
J2 = σ[(1-ε)T14 + ε2T24]
J2 = 5.67 x 10-8 + [(1-0.8) x 8004 + 0.6 x 5004]
J2 = 6.77 kW/m2
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Two infinitely large parallel plates 1 & 2, facing each other are separated by a very small gap. The plates are exchanging heat by thermal radiation and gap between them is filled with non-participating medium. Surface 1 is a black surface with temperature equal to and surface 2 is a grey surface with temperature equal to and emissivity equal to 0.8. Find out the radiosity for surface 2 in kW/m2a)6.76b)6.80c)6.81d)6.91Correct answer is option 'A'. Can you explain this answer?
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Two infinitely large parallel plates 1 & 2, facing each other are separated by a very small gap. The plates are exchanging heat by thermal radiation and gap between them is filled with non-participating medium. Surface 1 is a black surface with temperature equal to and surface 2 is a grey surface with temperature equal to and emissivity equal to 0.8. Find out the radiosity for surface 2 in kW/m2a)6.76b)6.80c)6.81d)6.91Correct answer is option 'A'. Can you explain this answer? for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about Two infinitely large parallel plates 1 & 2, facing each other are separated by a very small gap. The plates are exchanging heat by thermal radiation and gap between them is filled with non-participating medium. Surface 1 is a black surface with temperature equal to and surface 2 is a grey surface with temperature equal to and emissivity equal to 0.8. Find out the radiosity for surface 2 in kW/m2a)6.76b)6.80c)6.81d)6.91Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two infinitely large parallel plates 1 & 2, facing each other are separated by a very small gap. The plates are exchanging heat by thermal radiation and gap between them is filled with non-participating medium. Surface 1 is a black surface with temperature equal to and surface 2 is a grey surface with temperature equal to and emissivity equal to 0.8. Find out the radiosity for surface 2 in kW/m2a)6.76b)6.80c)6.81d)6.91Correct answer is option 'A'. Can you explain this answer?.
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