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Two larged if fuse gray parallel plates, separated by a small distance, have surface temperature of 400 K and 300 K. If the emissivities of the surfaces are 0.8 and the Stefan-Boltzmann constant is 5.67 × 10–8 W/ m2K4, the net radiation heat exchange rate in kW/m2 between the two plates is
[2013]
- a)0.66
- b)0.79
- c)0.99
- d)3.96
Correct answer is option 'A'. Can you explain this answer?
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Two larged if fuse gray parallel plates, separated by a small distance...
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Two larged if fuse gray parallel plates, separated by a small distance...
× 10^-8 W/(m^2·K^4), the rate of heat transfer by radiation between the plates can be calculated using the Stefan-Boltzmann Law:
Q = ε1 * σ * A * (T1^4 - T2^4)
Where:
Q = Heat transfer rate (in Watts)
ε1 = Emissivity of surface 1
σ = Stefan-Boltzmann constant (5.67 × 10^-8 W/(m^2·K^4))
A = Surface area of the plates (in square meters)
T1 = Temperature of surface 1 (in Kelvin)
T2 = Temperature of surface 2 (in Kelvin)
Given:
ε1 = ε2 = 0.8
T1 = 400 K
T2 = 300 K
Assuming the plates are rectangular, we can calculate the surface area as follows:
A = length * width
Let's say the length and width of the plates are L and W, respectively.
Now, we can calculate the rate of heat transfer:
Q = 0.8 * 5.67 × 10^-8 * (L * W) * (400^4 - 300^4)
Note: The units of length and width need to be in meters for the final result to be in Watts.
Please provide the values for length (L) and width (W), and I can calculate the rate of heat transfer for you.
Q = ε1 * σ * A * (T1^4 - T2^4)
Where:
Q = Heat transfer rate (in Watts)
ε1 = Emissivity of surface 1
σ = Stefan-Boltzmann constant (5.67 × 10^-8 W/(m^2·K^4))
A = Surface area of the plates (in square meters)
T1 = Temperature of surface 1 (in Kelvin)
T2 = Temperature of surface 2 (in Kelvin)
Given:
ε1 = ε2 = 0.8
T1 = 400 K
T2 = 300 K
Assuming the plates are rectangular, we can calculate the surface area as follows:
A = length * width
Let's say the length and width of the plates are L and W, respectively.
Now, we can calculate the rate of heat transfer:
Q = 0.8 * 5.67 × 10^-8 * (L * W) * (400^4 - 300^4)
Note: The units of length and width need to be in meters for the final result to be in Watts.
Please provide the values for length (L) and width (W), and I can calculate the rate of heat transfer for you.
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Two larged if fuse gray parallel plates, separated by a small distance, have surface temperature of 400 K and 300 K. If the emissivities of the surfaces are 0.8 and the Stefan-Boltzmann constant is 5.67 × 10–8 W/ m2K4, the net radiation heat exchange rate in kW/m2 between the two plates is[2013]a)0.66b)0.79c)0.99d)3.96Correct answer is option 'A'. Can you explain this answer?
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Two larged if fuse gray parallel plates, separated by a small distance, have surface temperature of 400 K and 300 K. If the emissivities of the surfaces are 0.8 and the Stefan-Boltzmann constant is 5.67 × 10–8 W/ m2K4, the net radiation heat exchange rate in kW/m2 between the two plates is[2013]a)0.66b)0.79c)0.99d)3.96Correct answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Two larged if fuse gray parallel plates, separated by a small distance, have surface temperature of 400 K and 300 K. If the emissivities of the surfaces are 0.8 and the Stefan-Boltzmann constant is 5.67 × 10–8 W/ m2K4, the net radiation heat exchange rate in kW/m2 between the two plates is[2013]a)0.66b)0.79c)0.99d)3.96Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two larged if fuse gray parallel plates, separated by a small distance, have surface temperature of 400 K and 300 K. If the emissivities of the surfaces are 0.8 and the Stefan-Boltzmann constant is 5.67 × 10–8 W/ m2K4, the net radiation heat exchange rate in kW/m2 between the two plates is[2013]a)0.66b)0.79c)0.99d)3.96Correct answer is option 'A'. Can you explain this answer?.
Two larged if fuse gray parallel plates, separated by a small distance, have surface temperature of 400 K and 300 K. If the emissivities of the surfaces are 0.8 and the Stefan-Boltzmann constant is 5.67 × 10–8 W/ m2K4, the net radiation heat exchange rate in kW/m2 between the two plates is[2013]a)0.66b)0.79c)0.99d)3.96Correct answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Two larged if fuse gray parallel plates, separated by a small distance, have surface temperature of 400 K and 300 K. If the emissivities of the surfaces are 0.8 and the Stefan-Boltzmann constant is 5.67 × 10–8 W/ m2K4, the net radiation heat exchange rate in kW/m2 between the two plates is[2013]a)0.66b)0.79c)0.99d)3.96Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two larged if fuse gray parallel plates, separated by a small distance, have surface temperature of 400 K and 300 K. If the emissivities of the surfaces are 0.8 and the Stefan-Boltzmann constant is 5.67 × 10–8 W/ m2K4, the net radiation heat exchange rate in kW/m2 between the two plates is[2013]a)0.66b)0.79c)0.99d)3.96Correct answer is option 'A'. Can you explain this answer?.
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