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A block of mass 1 kg is placed on a table . The block just starts to move, when a force of 10N is applied at 45 degree to the vertical to pull the block . The coefficient of friction b/w the table & the block. Take g=10 m/s^2?
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A block of mass 1 kg is placed on a table . The block just starts to m...
To find the coefficient of friction between the table and the block, we need to first determine the force of friction.
The force of friction can be calculated using the formula:
friction force = coefficient of friction * normal force
The normal force is the force exerted by the table on the block, which is equal to the weight of the block. The weight can be calculated using the formula:
weight = mass * acceleration due to gravity
Given that the mass of the block is 1 kg and the acceleration due to gravity is approximately 9.8 m/s^2, we can calculate the weight:
weight = 1 kg * 9.8 m/s^2 = 9.8 N
Next, we need to find the vertical and horizontal components of the applied force. The vertical component is given by:
vertical component = applied force * sin(angle)
The horizontal component is given by:
horizontal component = applied force * cos(angle)
Given that the applied force is 10 N and the angle is 45 degrees, we can calculate the vertical and horizontal components:
vertical component = 10 N * sin(45 degrees) ≈ 7.07 N
horizontal component = 10 N * cos(45 degrees) ≈ 7.07 N
Since the block just starts to move, the applied force is equal to the force of friction. Therefore, the force of friction is 10 N.
Finally, we can calculate the coefficient of friction:
coefficient of friction = force of friction / normal force
coefficient of friction = 10 N / 9.8 N ≈ 1.02
Therefore, the coefficient of friction between the table and the block is approximately 1.02.
The force of friction can be calculated using the formula:
friction force = coefficient of friction * normal force
The normal force is the force exerted by the table on the block, which is equal to the weight of the block. The weight can be calculated using the formula:
weight = mass * acceleration due to gravity
Given that the mass of the block is 1 kg and the acceleration due to gravity is approximately 9.8 m/s^2, we can calculate the weight:
weight = 1 kg * 9.8 m/s^2 = 9.8 N
Next, we need to find the vertical and horizontal components of the applied force. The vertical component is given by:
vertical component = applied force * sin(angle)
The horizontal component is given by:
horizontal component = applied force * cos(angle)
Given that the applied force is 10 N and the angle is 45 degrees, we can calculate the vertical and horizontal components:
vertical component = 10 N * sin(45 degrees) ≈ 7.07 N
horizontal component = 10 N * cos(45 degrees) ≈ 7.07 N
Since the block just starts to move, the applied force is equal to the force of friction. Therefore, the force of friction is 10 N.
Finally, we can calculate the coefficient of friction:
coefficient of friction = force of friction / normal force
coefficient of friction = 10 N / 9.8 N ≈ 1.02
Therefore, the coefficient of friction between the table and the block is approximately 1.02.
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A block of mass 1 kg is placed on a table . The block just starts to move, when a force of 10N is applied at 45 degree to the vertical to pull the block . The coefficient of friction b/w the table & the block. Take g=10 m/s^2?
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