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If one equation of a pair of dependent linear equations is -3x + 5y - 2 = 0. The second equation will be:
  • a)
    -6x + 10y - 4 = 0
  • b)
    6x - 10y - 4 = 0
  • c)
    6x + 10y - 4 = 0
  • d)
    -6x + 10y + 4 = 0
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
If one equation of a pair of dependent linear equations is -3x + 5y -...
The condition for dependent linear equations is
a1 / a2 = b1 / b2 ≠ c1 / c2
For option a,
a1 / a2 = b1 / b2 ≠ c1 / c2 = 1 / 2
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Most Upvoted Answer
If one equation of a pair of dependent linear equations is -3x + 5y -...
Solution:
Given equation is -3x + 5y - 2 = 0

We know that if two equations are dependent, then they will have the same solution.

To get the second equation, we can multiply the given equation by any constant value.

Let's multiply the given equation by 2.

-3x + 5y - 2 = 0
Multiplying both sides by 2, we get
-6x + 10y - 4 = 0

Hence the second equation is -6x + 10y - 4 = 0, which is option A.
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If one equation of a pair of dependent linear equations is -3x + 5y - 2 = 0. The second equation will be:a)-6x + 10y - 4 = 0b)6x - 10y - 4 = 0c)6x + 10y - 4 = 0d)-6x + 10y + 4 = 0Correct answer is option 'A'. Can you explain this answer?
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