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If the roots of the equation (a+ b2)x− 2b(a + c)x + (b2+c2) = 0 are equal then 

  • a)
    2b = ac

  • b)
    b= ac

  • c)
    b = 2ac/(a + c)

  • d)
    b = ac

  • e)
    b = 2ac

Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
If the roots of the equation(a2+ b2)x2− 2b(a + c)x + (b2+c2) = 0...
(a+ b2)x− 2b(a + c)x + (b2+c2) = 0
Roots are real and equal ∴ D = 0
D = b− 4ac = 0
⇒ [−2b(a+c)]− 4(a+ b2)(b+ c2) = 0
⇒ b2(a+ c+ 2ac) −(a2b2 + a2c2 + b4 + c2c2) = 0
⇒ b2a+ b2c+ 2acb− a2b− a2c− b4 − b2c2 = 0
⇒ 2acb− a2c− 2acb= 0
⇒ (b− ac)= 0
⇒ b2 = ac
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Community Answer
If the roots of the equation(a2+ b2)x2− 2b(a + c)x + (b2+c2) = 0...
We can rearrange the given equation to get:

(a^2 - b^2)x^2 + 2abx - 3ab = 0

The discriminant of this quadratic equation is:

D = (2ab)^2 - 4(a^2 - b^2)(-3ab)
= 4a^2b^2 + 12a^3b - 12ab^3

We want to find the conditions for which D is negative, which will imply that the quadratic equation has no real roots.

4a^2b^2 + 12a^3b - 12ab^3 < />

Dividing both sides by 4ab, we get:

ab + 3a^2 - 3b^2 < />

We can rewrite this inequality as:

ab < 3b^2="" -="" />

Now, we need to consider two cases:

1. b > 0: In this case, we can divide both sides by b^2 and get:

a/b < 3="" -="" />

Letting x = a/b, we can rewrite this as:

x^2 + 3x - 3 < />

This is a quadratic inequality that has solutions for:

-3 - sqrt(21) < x="" />< -3="" +="" />

Since x = a/b, this implies that:

a/b < -3="" -="" sqrt(21)="" or="" a/b="" /> -3 + sqrt(21)

2. b < 0:="" in="" this="" case,="" we="" can="" divide="" both="" sides="" by="" -b^2="" and="" />

-a/b < 3="" -="" />

Letting x = a/b, we can rewrite this as:

x^2 - 3x - 3 < />

This is a quadratic inequality that has solutions for:

(3 - sqrt(21)) < x="" />< (3="" +="" />

Since x = a/b, this implies that:

a/b < 3="" -="" sqrt(21)="" or="" a/b="" /> 3 + sqrt(21)

Therefore, the roots of the given quadratic equation are real if and only if:

a/b < -3="" -="" sqrt(21)="" or="" a/b="" /> -3 + sqrt(21) or a/b < 3="" -="" sqrt(21)="" or="" a/b="" /> 3 + sqrt(21)
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If the roots of the equation(a2+ b2)x2− 2b(a + c)x + (b2+c2) = 0are equal thena)2b = acb)b2= acc)b = 2ac/(a + c)d)b = ace)b = 2acCorrect answer is option 'B'. Can you explain this answer?
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