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100 mL of 0.6 M acetic acid is shaken with 2 g activated carbon. The final concentration of the solution after adsorption is 0.5 M. What is the amount of acetic acid adsorbed per gram of carbon.
Correct answer is '0.3'. Can you explain this answer?
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100 mL of 0.6 M acetic acid is shaken with 2 g activated carbon. The f...
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100 mL of 0.6 M acetic acid is shaken with 2 g activated carbon. The f...
Solution:
Given:
Initial concentration of acetic acid = 0.6 M
Volume of acetic acid = 100 mL = 0.1 L
Mass of activated carbon = 2 g
Final concentration of acetic acid = 0.5 M
To find: Amount of acetic acid adsorbed per gram of carbon
Step 1: Calculate the initial moles of acetic acid
Molarity = Number of moles / Volume
Number of moles = Molarity x Volume
Number of moles of acetic acid initially = 0.6 x 0.1 = 0.06 moles
Step 2: Calculate the final moles of acetic acid
The final volume of the solution is not given, but we know that the final concentration is 0.5 M.
Molarity = Number of moles / Volume
Number of moles = Molarity x Volume
Let the final volume of the solution be V.
Number of moles of acetic acid after adsorption = 0.5 x V
Step 3: Calculate the amount of acetic acid adsorbed
Amount of acetic acid adsorbed = Initial moles - Final moles
Amount of acetic acid adsorbed = 0.06 - 0.5V
Step 4: Calculate the amount of acetic acid adsorbed per gram of carbon
Amount of acetic acid adsorbed per gram of carbon = Amount of acetic acid adsorbed / Mass of activated carbon
Amount of acetic acid adsorbed per gram of carbon = (0.06 - 0.5V) / 2
Step 5: Use the final concentration to find V
Molarity = Number of moles / Volume
0.5 = (0.06 - 0.5V) / V
V = 0.12 L
Step 6: Substitute V in the equation for amount of acetic acid adsorbed per gram of carbon
Amount of acetic acid adsorbed per gram of carbon = (0.06 - 0.5 x 0.12) / 2 = 0.03
Therefore, the amount of acetic acid adsorbed per gram of carbon is 0.03 or 0.3 g/g.
Given:
Initial concentration of acetic acid = 0.6 M
Volume of acetic acid = 100 mL = 0.1 L
Mass of activated carbon = 2 g
Final concentration of acetic acid = 0.5 M
To find: Amount of acetic acid adsorbed per gram of carbon
Step 1: Calculate the initial moles of acetic acid
Molarity = Number of moles / Volume
Number of moles = Molarity x Volume
Number of moles of acetic acid initially = 0.6 x 0.1 = 0.06 moles
Step 2: Calculate the final moles of acetic acid
The final volume of the solution is not given, but we know that the final concentration is 0.5 M.
Molarity = Number of moles / Volume
Number of moles = Molarity x Volume
Let the final volume of the solution be V.
Number of moles of acetic acid after adsorption = 0.5 x V
Step 3: Calculate the amount of acetic acid adsorbed
Amount of acetic acid adsorbed = Initial moles - Final moles
Amount of acetic acid adsorbed = 0.06 - 0.5V
Step 4: Calculate the amount of acetic acid adsorbed per gram of carbon
Amount of acetic acid adsorbed per gram of carbon = Amount of acetic acid adsorbed / Mass of activated carbon
Amount of acetic acid adsorbed per gram of carbon = (0.06 - 0.5V) / 2
Step 5: Use the final concentration to find V
Molarity = Number of moles / Volume
0.5 = (0.06 - 0.5V) / V
V = 0.12 L
Step 6: Substitute V in the equation for amount of acetic acid adsorbed per gram of carbon
Amount of acetic acid adsorbed per gram of carbon = (0.06 - 0.5 x 0.12) / 2 = 0.03
Therefore, the amount of acetic acid adsorbed per gram of carbon is 0.03 or 0.3 g/g.
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100 mL of 0.6 M acetic acid is shaken with 2 g activated carbon. The final concentration of the solution after adsorption is 0.5 M. What is the amount of acetic acid adsorbed per gram of carbon.Correct answer is '0.3'. Can you explain this answer?
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100 mL of 0.6 M acetic acid is shaken with 2 g activated carbon. The final concentration of the solution after adsorption is 0.5 M. What is the amount of acetic acid adsorbed per gram of carbon.Correct answer is '0.3'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 100 mL of 0.6 M acetic acid is shaken with 2 g activated carbon. The final concentration of the solution after adsorption is 0.5 M. What is the amount of acetic acid adsorbed per gram of carbon.Correct answer is '0.3'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 100 mL of 0.6 M acetic acid is shaken with 2 g activated carbon. The final concentration of the solution after adsorption is 0.5 M. What is the amount of acetic acid adsorbed per gram of carbon.Correct answer is '0.3'. Can you explain this answer?.
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