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Three consecutive numbers are such that twice the first, 3 times the second, and 4 times the third together make 191. Find the least of the consecutive numbers.?
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Three consecutive numbers are such that twice the first, 3 times the s...
Problem: Three consecutive numbers are such that twice the first, 3 times the second, and 4 times the third together make 191. Find the least of the consecutive numbers.

Solution:

Let the three consecutive numbers be x, x+1, and x+2.

According to the problem,

2x + 3(x+1) + 4(x+2) = 191

Simplifying the above equation, we get:

2x + 3x + 3 + 4x + 8 = 191

9x + 11 = 191

9x = 180

x = 20

Therefore, the three consecutive numbers are 20, 21, and 22.

Hence, the least of the consecutive numbers is 20.
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Three consecutive numbers are such that twice the first, 3 times the s...
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Three consecutive numbers are such that twice the first, 3 times the second, and 4 times the third together make 191. Find the least of the consecutive numbers.?
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