Calculate the weight of CO having same number of oxygen atoms as present in 88g of CO2?

Question

Answer

Answer

Calculation of weight of CO

To calculate the weight of CO, we need to follow the given steps:

Step 1:

Calculate the number of oxygen atoms present in 88g of CO2.

Using the molecular mass of CO2:

Molecular mass of CO2 = 12 + 2(16) = 44g/mol

Number of moles of CO2 = Mass/Molecular mass = 88/44 = 2 moles

Number of oxygen atoms in 2 moles of CO2:

2 moles of CO2 = 2 x 6.022 x 10^23 molecules of CO2

1 molecule of CO2 = 2 atoms of oxygen

Therefore, 2 moles of CO2 = 2 x 6.022 x 10^23 x 2 = 2 x 12.044 x 10^23 atoms of oxygen

Step 2:

Calculate the number of moles of CO that will have the same number of oxygen atoms.

Since each molecule of CO has only 1 atom of oxygen, we need to find the number of moles of CO that will have the same number of oxygen atoms as present in 88g of CO2. This can be calculated as:

Number of moles of CO = Number of oxygen atoms/Number of oxygen atoms per molecule of CO

Number of oxygen atoms per molecule of CO = 1

Number of oxygen atoms = 2 x 12.044 x 10^23 = 24.088 x 10^23

Number of moles of CO = 24.088 x 10^23/1 = 24.088 x 10^23 moles

Step 3:

Calculate the weight of CO that will have the same number of oxygen atoms as present in 88g of CO2.

Using the molecular mass of CO:

Molecular mass of CO = 12 + 16 = 28g/mol

Weight of CO = Number of moles of CO x Molecular mass of CO

Weight of CO = 24.088 x 10^23 x 28 = 6.747 x 10^25 g

Conclusion:

The weight of CO that will have the same number of oxygen atoms as present in 88g of CO2 is 6.747 x 10^25 g.

Answer

Answer

2 moles of

. One molecule consists of 2 oxygen atoms.

No. of oxygen atoms

CO molecule has one oxygen atom.

Mass of CO containing

oxygen atoms

Answer

No of oxygen atoms in CO2 = 2× 88/44 × Avogadro's constant

no of oxygen atoms = weight of CO/28 × Avogadro's constant

no of oxygen atoms in CO2 = no of oxygen atoms in CO

2× 88/44 = weight of CO/28

weight of CO = 112 g

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