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Solve the equation Px Qy=P-Q and Qx-Py=P Q by substitution method and by cross-multiplication method?
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Solve the equation Px Qy=P-Q and Qx-Py=P Q by substitution method and ...
Substitution Method:
Let Qx = P - Q
Substituting in the equation, we get
Px Qy = P - Q
=> Px Qy = P – Q
=> Px = P – Q
=> Qy = 1

Cross-Multiplication Method:
PxQy = P - Q
Qx-Py = P Q
=> PxQ + PyQ = PQ
=> Q(Px + Py) = PQ
=> Q(P + Q) = PQ
=> P + Q = PQ
=> Qy = 1
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Solve the equation Px Qy=P-Q and Qx-Py=P Q by substitution method and by cross-multiplication method?
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