A father divided his property between two sons A and B and one daught...
Following common explanation, we get
The share of son A in total property = 4.6 lakhs
The share of son B in total property = 2.6 lakhs
The required difference = 4.6 – 2.6 = 2 lakhs
Hence, option A is correct.
Common explanation:
The total share of daughter = half of gold + 20% of land + 75% of cash amount
=
+ 20% of 5 lakhs + 75% of 80 thousand
= 3 lakhs + 1 lakhs + 60 thousand = 4 lakhs 60 thousand
Remaining Gold = 6 lakhs – 3 lakhs = 3 lakhs
Remaining Land = 5 lakhs – 1 lakhs = 4 lakhs
Remaining Cash = 80000 – 60000 = 20000
The share of son A = (1/2) of remaining gold + (3/4) of remaining land + (1/2) of remaining cash = 1.5 lakhs + 3 lakhs + 10 thousand = 4.6 lakhs
The share of son B = (1/2) of remaining gold + (1/4) of remaining land + (1/2) of remaining cash = 1.5 lakhs + 1 lakhs + 10 thousand = 2.6 lakhs.