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A 100 MW steam station uses coal of calorific value 6400 kcal/kg. Overall efficiency of the station is 25% and electrical efficiency is 92%. The coal consumption in kg per hour when the station is delivering its full rated output will be:?
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Calculation of coal consumption in a 100 MW steam station

Given:

Power output of the steam station (P) = 100 MW

Calorific value of coal (CV) = 6400 kcal/kg

Overall efficiency of the station (ηoverall) = 25%

Electrical efficiency of the station (ηelectrical) = 92%

Calculation:

The overall efficiency of the steam station is defined as the ratio of the useful energy output to the energy input. Therefore, the energy input to the station can be calculated as:

Energy input = Energy output / ηoverall

Energy output = Power output × time

Time = 1 hour (since we need to calculate coal consumption in kg per hour)

Therefore, Energy output = Power output × time = 100 MW × 1 hour = 100 MWh

Energy input = Energy output / ηoverall = (100 MWh) / 0.25 = 400 MWh


The electrical efficiency of the steam station is defined as the ratio of the electrical energy output to the energy input. Therefore, the electrical energy output of the station can be calculated as:

Electrical energy output = Power output × time × ηelectrical

Electrical energy output = 100 MW × 1 hour × 0.92 = 92 MWh


The energy input to the station is 400 MWh, and the calorific value of coal is 6400 kcal/kg. Therefore, the coal consumption in kg per hour can be calculated as:

Coal consumption (kg/h) = Energy input / (CV × efficiency)

Efficiency = (Electrical energy output / Energy input) = 92 MWh / 400 MWh = 0.23

Coal consumption (kg/h) = 400 MWh / (6400 kcal/kg × 0.23) = 30303.03 kg/h

Answer:

The coal consumption in kg per hour when the steam station is delivering its full rated output will be 30303.03 kg/h.
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A 100 MW steam station uses coal of calorific value 6400 kcal/kg. Overall efficiency of the station is 25% and electrical efficiency is 92%. The coal consumption in kg per hour when the station is delivering its full rated output will be:?
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