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On keeping iron nails in copper sulphate solution for two hours, the colour of solution changes
  • a)
    from colourless to blue
  • b)
    from light green to blue
  • c)
    from blue to light green
  • d)
    from light green to colourless
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
On keeping iron nails in copper sulphate solution for two hours, the c...
When an iron nail immersed in the solution of copper sulphate than iron displaces copper from the solution of copper sulphate because iron is more reactive than copper. Therefore copper sulphate solution colour changes from blue to pale green.
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On keeping iron nails in copper sulphate solution for two hours, the c...
Explanation:
When iron nails are kept in copper sulphate solution, a chemical reaction takes place. The following changes occur in the solution:

Step 1: Dissolution of copper sulphate
When copper sulphate is added to water, it dissolves in it. The solution formed is light blue in colour.

Step 2: Chemical reaction between iron and copper sulphate
When iron nails are added to the copper sulphate solution, a displacement reaction takes place. The iron reacts with the copper sulphate to form iron sulphate and copper.

Fe + CuSO4 → FeSO4 + Cu

As a result of this reaction, the blue colour of the copper sulphate solution fades.

Step 3: Formation of iron sulphate
Iron nails react with copper sulphate to form iron sulphate. The iron sulphate formed in the reaction dissolves in the solution. The colour of the solution changes from blue to light green.

Fe + CuSO4 → FeSO4 + Cu

Conclusion:
Thus, the correct answer is option 'C'. When iron nails are kept in copper sulphate solution for two hours, the colour of the solution changes from blue to light green. This is because the iron nails react with the copper sulphate to form iron sulphate and copper. The iron sulphate formed dissolves in the solution, leading to the change in colour.
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On keeping iron nails in copper sulphate solution for two hours, the colour of solution changesa)from colourless to blueb)from light green to bluec)from blue to light greend)from light green to colourlessCorrect answer is option 'C'. Can you explain this answer?
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