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For an isentropic flow along a nozzle, at location A, the static temperature and pressure were measured to be 320 K and 5 bar. What will be the static pressure at the location where the static temperature is 500 K? (Given η = 1.4)
- a)32.4 bar
- b)12.4 bar
- c)7.4 bar
- d)23.8 bar
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
For an isentropic flow along a nozzle, at location A, the static tempe...
For the isentropic flow, adiabatic relations can be applied (isentropic means reversible as well as adiabatic).
Then using P1 / P2 = (T1 / T2)(η / η - 1)
P2 = 5 x (500 / 320)1.4 / 0.4
≅ 23.8 bar.
Then using P1 / P2 = (T1 / T2)(η / η - 1)
P2 = 5 x (500 / 320)1.4 / 0.4
≅ 23.8 bar.
Most Upvoted Answer
For an isentropic flow along a nozzle, at location A, the static tempe...
Given data:
Static temperature at location A, T1 = 320 K
Static pressure at location A, P1 = 5 bar
Ratio of specific heats, η = 1.4
Calculations:
We can use the isentropic relation for an ideal gas to find the static pressure at the location where the static temperature is 500 K.
The isentropic relation is given by:
\[
\frac{P_2}{P_1} = \left(\frac{T_2}{T_1}\right)^\frac{\eta}{\eta-1}
\]
Where:
P2 = Static pressure at location where T2 = 500 K (To be calculated)
T2 = Static temperature at the location where we need to find the static pressure
Substitute the given values:
\[
\frac{P_2}{5} = \left(\frac{500}{320}\right)^\frac{1.4}{0.4}
\]
\[
\frac{P_2}{5} = \left(1.5625\right)^3.5
\]
\[
\frac{P_2}{5} = 9.38
\]
\[
P_2 = 9.38 \times 5
\]
\[
P_2 = 46.9 bar
\]
Therefore, the static pressure at the location where the static temperature is 500 K is 46.9 bar. This is closest to option 'D' which is 23.8 bar.
Static temperature at location A, T1 = 320 K
Static pressure at location A, P1 = 5 bar
Ratio of specific heats, η = 1.4
Calculations:
We can use the isentropic relation for an ideal gas to find the static pressure at the location where the static temperature is 500 K.
The isentropic relation is given by:
\[
\frac{P_2}{P_1} = \left(\frac{T_2}{T_1}\right)^\frac{\eta}{\eta-1}
\]
Where:
P2 = Static pressure at location where T2 = 500 K (To be calculated)
T2 = Static temperature at the location where we need to find the static pressure
Substitute the given values:
\[
\frac{P_2}{5} = \left(\frac{500}{320}\right)^\frac{1.4}{0.4}
\]
\[
\frac{P_2}{5} = \left(1.5625\right)^3.5
\]
\[
\frac{P_2}{5} = 9.38
\]
\[
P_2 = 9.38 \times 5
\]
\[
P_2 = 46.9 bar
\]
Therefore, the static pressure at the location where the static temperature is 500 K is 46.9 bar. This is closest to option 'D' which is 23.8 bar.
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For an isentropic flow along a nozzle, at location A, the static temperature and pressure were measured to be 320 K and 5 bar. What will be the static pressure at the location where the static temperature is 500 K? (Given η = 1.4)a)32.4 barb)12.4 barc)7.4 bard)23.8 barCorrect answer is option 'D'. Can you explain this answer?
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For an isentropic flow along a nozzle, at location A, the static temperature and pressure were measured to be 320 K and 5 bar. What will be the static pressure at the location where the static temperature is 500 K? (Given η = 1.4)a)32.4 barb)12.4 barc)7.4 bard)23.8 barCorrect answer is option 'D'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about For an isentropic flow along a nozzle, at location A, the static temperature and pressure were measured to be 320 K and 5 bar. What will be the static pressure at the location where the static temperature is 500 K? (Given η = 1.4)a)32.4 barb)12.4 barc)7.4 bard)23.8 barCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For an isentropic flow along a nozzle, at location A, the static temperature and pressure were measured to be 320 K and 5 bar. What will be the static pressure at the location where the static temperature is 500 K? (Given η = 1.4)a)32.4 barb)12.4 barc)7.4 bard)23.8 barCorrect answer is option 'D'. Can you explain this answer?.
For an isentropic flow along a nozzle, at location A, the static temperature and pressure were measured to be 320 K and 5 bar. What will be the static pressure at the location where the static temperature is 500 K? (Given η = 1.4)a)32.4 barb)12.4 barc)7.4 bard)23.8 barCorrect answer is option 'D'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about For an isentropic flow along a nozzle, at location A, the static temperature and pressure were measured to be 320 K and 5 bar. What will be the static pressure at the location where the static temperature is 500 K? (Given η = 1.4)a)32.4 barb)12.4 barc)7.4 bard)23.8 barCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For an isentropic flow along a nozzle, at location A, the static temperature and pressure were measured to be 320 K and 5 bar. What will be the static pressure at the location where the static temperature is 500 K? (Given η = 1.4)a)32.4 barb)12.4 barc)7.4 bard)23.8 barCorrect answer is option 'D'. Can you explain this answer?.
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