Two trains move in the same direction at 50 kmph and 32 kmph respectiv...
Solution :
relative velocity in same direction =18
as a man observes the elapse not the whole train so here only the length of the faster train will be taken
into account not the slower train so here comes the equation 18(5/18)mps* 15=75
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Two trains move in the same direction at 50 kmph and 32 kmph respectiv...
Given:
Two trains are moving in the same direction.
Speed of the first train = 50 km/h
Speed of the second train = 32 km/h
The man in the slower train observes that it takes 15 seconds for the faster train to completely pass by him.
To find:
Length of the faster train.
Explanation:
When two objects are moving in the same direction, the relative speed between them is the difference of their individual speeds.
Let's assume the length of the faster train is 'x' meters.
Calculating relative speed:
Relative speed = Speed of the faster train - Speed of the slower train
Relative speed = (50 km/h - 32 km/h) = 18 km/h
Since the relative speed is given in km/h, we need to convert it to m/s for further calculations.
Speed in m/s = (18 km/h) * (1000 m/km) * (1/3600 h/s) = 5 m/s
Calculating the time taken by the faster train to completely pass by the man:
The time taken to cover a distance is given by the formula:
Time = Distance / Speed
In this case, the distance is the length of the faster train (x) and the speed is the relative speed (5 m/s).
So, the time taken by the faster train to completely pass by the man is given by:
15 seconds = x / 5 m/s
Solving the equation:
To find the length of the faster train, we need to solve the equation:
x = 15 seconds * 5 m/s
x = 75 meters
Conclusion:
Therefore, the length of the faster train is 75 meters.
Hence, option B is the correct answer.