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The molality of the solution prepared by dissolving 125ml of pure methanol (d = 0.8m/l) in 375g of ethanol is:plzzz answer this question quickely
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The molality of the solution prepared by dissolving 125ml of pure meth...
Calculating Molality of the Solution:
To calculate the molality of the solution, we first need to determine the moles of solute (methanol) and the mass of solvent (ethanol).
Step 1: Calculate Moles of Methanol:
Given that the density of methanol is 0.8 g/ml, we can calculate the mass of methanol:
Volume of methanol = 125 ml
Density of methanol = 0.8 g/ml
Mass of methanol = Volume x Density = 125 ml x 0.8 g/ml = 100 g
Next, we need to convert the mass of methanol to moles using its molar mass:
Molar mass of methanol (CH3OH) = 32 g/mol
Moles of methanol = Mass / Molar mass = 100 g / 32 g/mol = 3.125 mol
Step 2: Calculate Mass of Ethanol:
Given that the mass of ethanol is 375 g, we can directly use this value as the mass of the solvent.
Step 3: Calculate Molality of the Solution:
Molality (m) is defined as moles of solute per kilogram of solvent. Since the mass of ethanol is in grams, we need to convert it to kilograms:
Mass of ethanol = 375 g = 0.375 kg
Now, we can calculate the molality of the solution using the formula:
Molality (m) = Moles of solute / Mass of solvent in kg
Molality = 3.125 mol / 0.375 kg = 8.33 mol/kg
Therefore, the molality of the solution prepared by dissolving 125 ml of pure methanol in 375 g of ethanol is 8.33 mol/kg.
To calculate the molality of the solution, we first need to determine the moles of solute (methanol) and the mass of solvent (ethanol).
Step 1: Calculate Moles of Methanol:
Given that the density of methanol is 0.8 g/ml, we can calculate the mass of methanol:
Volume of methanol = 125 ml
Density of methanol = 0.8 g/ml
Mass of methanol = Volume x Density = 125 ml x 0.8 g/ml = 100 g
Next, we need to convert the mass of methanol to moles using its molar mass:
Molar mass of methanol (CH3OH) = 32 g/mol
Moles of methanol = Mass / Molar mass = 100 g / 32 g/mol = 3.125 mol
Step 2: Calculate Mass of Ethanol:
Given that the mass of ethanol is 375 g, we can directly use this value as the mass of the solvent.
Step 3: Calculate Molality of the Solution:
Molality (m) is defined as moles of solute per kilogram of solvent. Since the mass of ethanol is in grams, we need to convert it to kilograms:
Mass of ethanol = 375 g = 0.375 kg
Now, we can calculate the molality of the solution using the formula:
Molality (m) = Moles of solute / Mass of solvent in kg
Molality = 3.125 mol / 0.375 kg = 8.33 mol/kg
Therefore, the molality of the solution prepared by dissolving 125 ml of pure methanol in 375 g of ethanol is 8.33 mol/kg.
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The molality of the solution prepared by dissolving 125ml of pure meth...
8.400 m
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The molality of the solution prepared by dissolving 125ml of pure methanol (d = 0.8m/l) in 375g of ethanol is:plzzz answer this question quickely for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The molality of the solution prepared by dissolving 125ml of pure methanol (d = 0.8m/l) in 375g of ethanol is:plzzz answer this question quickely covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The molality of the solution prepared by dissolving 125ml of pure methanol (d = 0.8m/l) in 375g of ethanol is:plzzz answer this question quickely.
The molality of the solution prepared by dissolving 125ml of pure methanol (d = 0.8m/l) in 375g of ethanol is:plzzz answer this question quickely for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about The molality of the solution prepared by dissolving 125ml of pure methanol (d = 0.8m/l) in 375g of ethanol is:plzzz answer this question quickely covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The molality of the solution prepared by dissolving 125ml of pure methanol (d = 0.8m/l) in 375g of ethanol is:plzzz answer this question quickely.
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