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6. If α and β are the zeroes of a quadratic polynomial x^2 x – 2 then find the value of (1/alpha +1/beta)?
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6. If α and β are the zeroes of a quadratic polynomial x^2 x – 2 then ...
Given:
The quadratic polynomial is x^2 + x - 2.
Let α and β be the zeroes of the polynomial.

To Find:
The value of (1/α) + (1/β).

Solution:

The sum of the zeroes of a quadratic polynomial is given by the formula:
α + β = -b/a

The product of the zeroes of a quadratic polynomial is given by the formula:
α * β = c/a

In this case, the quadratic polynomial is x^2 + x - 2, so the values of a, b, and c are:
a = 1, b = 1, c = -2

Using the formulas above, we can calculate the values of α + β and α * β:
α + β = -1/1 = -1
α * β = -2/1 = -2

Now, let's find the value of (1/α) + (1/β):
(1/α) + (1/β) = (α + β)/(α * β)

Substituting the values we found earlier:
(1/α) + (1/β) = (-1)/(-2) = 1/2

Therefore, the value of (1/α) + (1/β) is 1/2.
Community Answer
6. If α and β are the zeroes of a quadratic polynomial x^2 x – 2 then ...
X² ke baad kya h ...
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6. If α and β are the zeroes of a quadratic polynomial x^2 x – 2 then find the value of (1/alpha +1/beta)?
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