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Find the value of ‘k’ if the equations have many solutions 3x-4y=5 & 6x (2k-1)y= 10?
Most Upvoted Answer
Find the value of ‘k’ if the equations have many solutions 3x-4y=5 & 6...
If the equation have many solutions then, a1/a2 = b1/b2 = c1/c2

3/6= -4/2k-1
1/2 = -4/2k-1
2k-1 = -8
2k = -7
k = -7/2
Community Answer
Find the value of ‘k’ if the equations have many solutions 3x-4y=5 & 6...
To determine the value of 'k' if the equations have many solutions, we need to find the condition under which the equations are dependent and have an infinite number of solutions.

We can do this by checking if the ratio of the coefficients of x and y is the same in both equations.

In the given equation, 3x - 4y = 5, the ratio of the coefficients is 3/-4 = -3/4.

Now let's introduce 'k' into the equation: k(3x - 4y) = k(5).

Expanding the equation, we get: 3kx - 4ky = 5k.

Comparing this equation with the original equation, we see that the ratio of the coefficients is still 3/-4 = -3/4.

Therefore, the value of 'k' can be any real number except 0.

So, the value of 'k' is any real number except 0.
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