The sum of the present ages of a father and his son is 100 years. 5 Y...
Let the present ages of father and son be x and y. given, x + y = 100
⇒ x = 100 – y ..............(i)
Five years ago, their ages was in ratio of 2 : 1
x − 5 = 2y − 10x − 5 = 2y − 10
2y − x − 5 = 0 2y − x − 5 = 0
x − 2y + 5 = 0 x − 2y + 5 = 0
putting (i) in eq. (ii)
100 − y − 2y + 5 = 0 100 − y − 2y + 5 = 0
100 − 3y + 55 = 0 100 − 3y + 55 = 0
105 = 3y 105 = 3y
y = 1053 = 35 = 105/3 = 35
putting value of y in eq. (i)(?)
x = 100 − 35 = 65x = 100 − 35 = 65
So, the ratio of present ages of father 8 son ⇒ xy = 6535 ⇒ x/y = 65/35
(x:y ⇒ 17:11)(x:y ⇒ 17:11) Hence, option (B) is correct