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why root 5 is irrational ?
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Let us demonstrate that √5 is an irrational number by proving the theorem.

Using the method of contradiction, it is possible to demonstrate the answer to this question. Let’s take it for granted that the number √5 is a rational number. If √5 is rational, then it may be expressed as an equation of the type a/b, here integers are a and b. 

√5/1 = a/b

√5b = a

Bringing both sides into balance,

5b2 = a2

b2 = a2/5 —- (1)

This indicates that a2 is divided by 5.

That indicates that it can also divide a.

a/5 = c

a = 5c

On squaring, we get

a2 = 25c2

Replace a2 in the equation with its value (1).

5b2 = 25c2

b2 = 5c2

b2/5 = c2

This indicates that b2 may be divided by 5, and hence, b can likewise be divided by 5. Since this is the case, a and b share the factor 5 in common. However, this goes against the fact that a and b are in the coprime position. The fact that we made the assumption that √5 is a rational number led to the formation of this contradiction. As a result, we are forced to the conclusion that √5 is irrational.

Therefore √5 is an irrational number.

Courtesy ; Unacademy
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