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The kinetic energy of a body initially at rest is found to be proportional to t^4?
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The kinetic energy of a body initially at rest is found to be proporti...
Explanation:


  • Definition of Kinetic Energy: Kinetic energy is the energy of motion of a body. It is directly proportional to the mass of the body and the square of its velocity.

  • Initial Velocity: As the body is initially at rest, its initial velocity is zero.

  • Proportional to t^4: According to the given statement, the kinetic energy of the body is proportional to t^4.

  • Derivation: Let the mass of the body be m and its velocity at time t be v. Then, the kinetic energy of the body can be expressed as:

    K.E. = (1/2)mv^2

    As the body is initially at rest, v = 0.

    Therefore, K.E. = (1/2)m(0)^2 = 0

    Now, according to the given statement, the kinetic energy is proportional to t^4.

    Therefore, K.E. = kt^4, where k is a constant of proportionality.

    Substituting this value of K.E. in the equation (1/2)mv^2, we get:

    (1/2)mv^2 = kt^4

    v^2 = 2kt^4/m

    v = (2kt^4/m)^1/2

    Thus, the velocity of the body at time t is proportional to t^2.


Conclusion:


  • Hence, we can conclude that the velocity of the body is proportional to t^2 and the kinetic energy is proportional to t^4.

Community Answer
The kinetic energy of a body initially at rest is found to be proporti...
Yes K.E. is proportional to t⁴
Given : u = 0 m/s
let acceleration be constant
We know K.E.= ½mv²
From first law of motion ,we get
v = u + at
v= 0 + at
v= at
Therefore , K.E.=½mv²
=½m(at)²
=½ma²t²
=ma⁴t⁴
Hence ,kinetic energy is proportional to t⁴.
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