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When the gases sulphur dioxide and hydrogen sulphide mix in the presence of water, the reaction SO2 + 2H2S → 2H2O + 3S occurs. Here hydrogen sulphide is acting as
  • a)
    an oxidising agent
  • b)
    a reducing agent
  • c)
    a dehydrating agent
  • d)
    a catalyst
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
When the gases sulphur dioxide and hydrogen sulphide mix in the presen...
2H2O → 3S + 2H2SO4

This reaction produces sulfur and sulfuric acid.
Free Test
Community Answer
When the gases sulphur dioxide and hydrogen sulphide mix in the presen...
A chemical which donates electrons to other then it is called a reducing agent because the chemical undergoes oxidation and reduces other chemicals. A chemical which accepts electrons from others is called an oxidizing agent because the chemical is going to make others undergo oxidation.

Complete answer:
- In the question is asked to find the role of hydrogen sulphide in the given reaction.
- The given reaction is as follows.

SO2+2H2S→2H2O+3SSO2+2H2S→2H2O+3S

 
- In the above reaction one mole of sulphur dioxide reacts with two moles of hydrogen sulphide and forms two moles of water and three moles of sulphur as the products.
- The oxidation state of sulphur in sulphur dioxide is 
x+2(−2)=0x+2(−2)=0
x=4x=4
Here x = oxidation state of the sulphur on sulphur dioxide.
- The oxidation state of the pure sulphur formed as the product is 0.
- Means the oxidation state of sulphur in sulphur dioxide is 4 and it decreases to ‘0’ after completion of the reaction.
- So, the sulphur dioxide got reduced by accepting electrons from hydrogen sulphide. 
- Means sulphur dioxide is a oxidizing agent and hydrogen sulphide is a reducing agent.
- Therefore the role of hydrogen sulphide in the given reaction is a reducing agent.

So, the correct option is B. 

Note: 
The oxidation state of sulphur in hydrogen sulphide is 
x+2(1)=0x+2(1)=0
x=−2x=−2
Here x =oxidation state of sulphur in hydrogen sulphide. 
The oxidation state of sulphur in hydrogen sulphide is -2 it is changed to ‘0’ (oxidation state of sulphur produced in reaction as the product). So, hydrogen sulphide is oxidized and acts as a reducing agent in the given reaction.
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When the gases sulphur dioxide and hydrogen sulphide mix in the presence ofwater, the reaction SO2 + 2H2S → 2H2O + 3S occurs. Here hydrogen sulphide isacting asa)an oxidising agentb)a reducing agentc)a dehydrating agentd)a catalystCorrect answer is option 'B'. Can you explain this answer?
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When the gases sulphur dioxide and hydrogen sulphide mix in the presence ofwater, the reaction SO2 + 2H2S → 2H2O + 3S occurs. Here hydrogen sulphide isacting asa)an oxidising agentb)a reducing agentc)a dehydrating agentd)a catalystCorrect answer is option 'B'. Can you explain this answer? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about When the gases sulphur dioxide and hydrogen sulphide mix in the presence ofwater, the reaction SO2 + 2H2S → 2H2O + 3S occurs. Here hydrogen sulphide isacting asa)an oxidising agentb)a reducing agentc)a dehydrating agentd)a catalystCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When the gases sulphur dioxide and hydrogen sulphide mix in the presence ofwater, the reaction SO2 + 2H2S → 2H2O + 3S occurs. Here hydrogen sulphide isacting asa)an oxidising agentb)a reducing agentc)a dehydrating agentd)a catalystCorrect answer is option 'B'. Can you explain this answer?.
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