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Study the given cross showing self pollination in F1 and answer the questions
RRYY × rryy Parents
(Round Yellow) (Wrinkled Green)
RrYy × ________ F1 generation
(Round Yellow)
Q. The ratio of the combination of characters in the F2 progeny is:
- a)3:1
- b)1:2:1
- c)1:1:1
- d)9:3:3:1
Correct answer is option 'D'. Can you explain this answer?
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Study the given cross showing self pollination in F1 and answer the q...
Mendel crossed pea plants having round green seeds (RRyy) with pea plants having wrinkled yellow seeds (rrYY).
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An example of dihybrid cross: Since, the F1 plants are formed after crossing pea plants having green round seeds and pea plants having yellow wrinkled seeds. F1 generation will have both these characters in them. However, as we know that yellow seed colour and round seeds are dominant characters, therefore, the F1 plants will have yellow round seeds.
Then, this F1 progeny was self-pollinated and the F2 progeny was found to have yellow round seeds, green round seeds, yellow wrinkled seeds and green wrinkled seeds in the ratio 9:3:3:1.
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Study the given cross showing self pollination in F1 and answer the q...
Understanding the Cross: RRYY × rryy
In this genetic cross, we start with two parent plants:
- RRYY (Round Yellow)
- rryy (Wrinkled Green)
The traits are represented by the alleles:
- R = Round seed shape (dominant)
- r = Wrinkled seed shape (recessive)
- Y = Yellow seed color (dominant)
- y = Green seed color (recessive)
F1 Generation
When we cross these parents, the F1 generation consists of all heterozygous individuals:
- RrYy (Round Yellow)
All F1 plants display the dominant traits of round shape and yellow color.
F2 Generation
When F1 plants self-pollinate (RrYy × RrYy), we can determine the F2 generation's trait ratios using the Punnett square method.
Creating the Punnett Square
We will consider the gametes produced by the F1 plants:
- Gametes from RrYy: RY, Ry, rY, ry
When we set up a 4x4 Punnett square, we get the following combinations for the F2 generation:
1. RRYY (Round Yellow)
2. RRYy (Round Yellow)
3. RrYY (Round Yellow)
4. RrYy (Round Yellow)
5. Rryy (Round Green)
6. rrYY (Wrinkled Yellow)
7. rrYy (Wrinkled Yellow)
8. rryy (Wrinkled Green)
Phenotypic Ratio
The resulting phenotypic ratio from the F2 generation is:
- 9 Round Yellow
- 3 Round Green
- 3 Wrinkled Yellow
- 1 Wrinkled Green
Thus, the ratio of the combinations of characters in the F2 progeny is:
9:3:3:1
This confirms that the correct answer is option 'D'.
In this genetic cross, we start with two parent plants:
- RRYY (Round Yellow)
- rryy (Wrinkled Green)
The traits are represented by the alleles:
- R = Round seed shape (dominant)
- r = Wrinkled seed shape (recessive)
- Y = Yellow seed color (dominant)
- y = Green seed color (recessive)
F1 Generation
When we cross these parents, the F1 generation consists of all heterozygous individuals:
- RrYy (Round Yellow)
All F1 plants display the dominant traits of round shape and yellow color.
F2 Generation
When F1 plants self-pollinate (RrYy × RrYy), we can determine the F2 generation's trait ratios using the Punnett square method.
Creating the Punnett Square
We will consider the gametes produced by the F1 plants:
- Gametes from RrYy: RY, Ry, rY, ry
When we set up a 4x4 Punnett square, we get the following combinations for the F2 generation:
1. RRYY (Round Yellow)
2. RRYy (Round Yellow)
3. RrYY (Round Yellow)
4. RrYy (Round Yellow)
5. Rryy (Round Green)
6. rrYY (Wrinkled Yellow)
7. rrYy (Wrinkled Yellow)
8. rryy (Wrinkled Green)
Phenotypic Ratio
The resulting phenotypic ratio from the F2 generation is:
- 9 Round Yellow
- 3 Round Green
- 3 Wrinkled Yellow
- 1 Wrinkled Green
Thus, the ratio of the combinations of characters in the F2 progeny is:
9:3:3:1
This confirms that the correct answer is option 'D'.
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Study the given cross showing self pollination in F1 and answer the questionsRRYY × rryy Parents(Round Yellow) (Wrinkled Green)RrYy × ________ F1 generation(Round Yellow)Q. The ratio of the combination of characters in the F2 progeny is:a)3:1b)1:2:1c)1:1:1d)9:3:3:1Correct answer is option 'D'. Can you explain this answer?
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Study the given cross showing self pollination in F1 and answer the questionsRRYY × rryy Parents(Round Yellow) (Wrinkled Green)RrYy × ________ F1 generation(Round Yellow)Q. The ratio of the combination of characters in the F2 progeny is:a)3:1b)1:2:1c)1:1:1d)9:3:3:1Correct answer is option 'D'. Can you explain this answer? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about Study the given cross showing self pollination in F1 and answer the questionsRRYY × rryy Parents(Round Yellow) (Wrinkled Green)RrYy × ________ F1 generation(Round Yellow)Q. The ratio of the combination of characters in the F2 progeny is:a)3:1b)1:2:1c)1:1:1d)9:3:3:1Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Study the given cross showing self pollination in F1 and answer the questionsRRYY × rryy Parents(Round Yellow) (Wrinkled Green)RrYy × ________ F1 generation(Round Yellow)Q. The ratio of the combination of characters in the F2 progeny is:a)3:1b)1:2:1c)1:1:1d)9:3:3:1Correct answer is option 'D'. Can you explain this answer?.
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