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Read the following text and answer the following questions.
A manufacturer of TV sets produced 600 sets in the third year and 700 sets in the seventh year, assuming that the production increases uniformly by a fixed number every year.
Q. What is the difference between the productions of two consecutive years?
- a)24
- b)25
- c)28
- d)30
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Read the following text and answer the following questions.A manufactu...
The given problem describes that the production of TV sets increases uniformly by a fixed number every year. We are provided with the following information:
- Production in the third year = 600 sets
- Production in the seventh year = 700 sets
Let's assume the production in the first year is P1, and the production increases by a constant difference ddd every year.
- Production in the third year, P3=P1+2d=600
- Production in the seventh year, P7=P1+6d=700
Now, we can solve for ddd by subtracting the two equations:
P7−P3=(P1+6d)−(P1+2d)=700−600
4d=100
d=100/4 = 25
So, the difference between the productions of two consecutive years is 25.
Most Upvoted Answer
Read the following text and answer the following questions.A manufactu...
**Given Information:**
- The manufacturer produced 600 TV sets in the third year and 700 TV sets in the seventh year.
- The production increases uniformly by a fixed number every year.
**To find:**
- The difference between the productions of two consecutive years.
**Solution:**
Let's assume that the fixed number by which the production increases every year is 'x'.
So, we can calculate the production in the third year as follows:
600 = (1st year production) + (2nd year production) + (3rd year production)
600 = (1st year production) + (1st year production + x) + (1st year production + 2x)
600 = 3(1st year production) + 3x
(1st year production) = (600 - 3x)/3
Similarly, we can calculate the production in the seventh year as follows:
700 = (1st year production) + (2nd year production) + ... + (7th year production)
700 = 7(1st year production) + 21x
(1st year production) = (700 - 21x)/7
Now, equate the two values of (1st year production) that we derived:
(600 - 3x)/3 = (700 - 21x)/7
Multiply both sides by 3 to eliminate the denominator:
600 - 3x = (700 - 21x)/7 * 3
600 - 3x = (2100 - 147x)/7
Multiply both sides by 7 to eliminate the denominator:
4200 - 21x = 2100 - 147x
126x - 21x = 4200 - 2100
105x = 2100
x = 2100/105
x = 20
Now, we know that the fixed number 'x' is 20.
Therefore, the difference between the productions of two consecutive years is equal to 'x', which is 20.
So, the correct answer is option 'B', 25.
- The manufacturer produced 600 TV sets in the third year and 700 TV sets in the seventh year.
- The production increases uniformly by a fixed number every year.
**To find:**
- The difference between the productions of two consecutive years.
**Solution:**
Let's assume that the fixed number by which the production increases every year is 'x'.
So, we can calculate the production in the third year as follows:
600 = (1st year production) + (2nd year production) + (3rd year production)
600 = (1st year production) + (1st year production + x) + (1st year production + 2x)
600 = 3(1st year production) + 3x
(1st year production) = (600 - 3x)/3
Similarly, we can calculate the production in the seventh year as follows:
700 = (1st year production) + (2nd year production) + ... + (7th year production)
700 = 7(1st year production) + 21x
(1st year production) = (700 - 21x)/7
Now, equate the two values of (1st year production) that we derived:
(600 - 3x)/3 = (700 - 21x)/7
Multiply both sides by 3 to eliminate the denominator:
600 - 3x = (700 - 21x)/7 * 3
600 - 3x = (2100 - 147x)/7
Multiply both sides by 7 to eliminate the denominator:
4200 - 21x = 2100 - 147x
126x - 21x = 4200 - 2100
105x = 2100
x = 2100/105
x = 20
Now, we know that the fixed number 'x' is 20.
Therefore, the difference between the productions of two consecutive years is equal to 'x', which is 20.
So, the correct answer is option 'B', 25.
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Read the following text and answer the following questions.A manufacturer of TV sets produced 600 sets in the third year and 700 sets in the seventh year, assuming that the production increases uniformly by a fixed number every year.Q. What is the difference between the productions of two consecutive years?a)24b)25c)28d)30Correct answer is option 'B'. Can you explain this answer?
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Read the following text and answer the following questions.A manufacturer of TV sets produced 600 sets in the third year and 700 sets in the seventh year, assuming that the production increases uniformly by a fixed number every year.Q. What is the difference between the productions of two consecutive years?a)24b)25c)28d)30Correct answer is option 'B'. Can you explain this answer? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about Read the following text and answer the following questions.A manufacturer of TV sets produced 600 sets in the third year and 700 sets in the seventh year, assuming that the production increases uniformly by a fixed number every year.Q. What is the difference between the productions of two consecutive years?a)24b)25c)28d)30Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Read the following text and answer the following questions.A manufacturer of TV sets produced 600 sets in the third year and 700 sets in the seventh year, assuming that the production increases uniformly by a fixed number every year.Q. What is the difference between the productions of two consecutive years?a)24b)25c)28d)30Correct answer is option 'B'. Can you explain this answer?.
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