A box contains 90 discs which are numbered from 1 to 90. If one disc i...
1. Perfect squares b/w 1 to 90= 4, 9, 16, 25, 36, 49, 64, 81
i.e. no. of perfect squares (favourable outcomes)= 8
Therefore, probability (getting a perfect square)= 8/90 = 4/45
2. No.s divisible by 5 b/w 1 to 90= 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90
i.e. favourable outcomes= 18
Therefore, probability (getting a no. divisible by 5)= 18/90 = 1/5
A box contains 90 discs which are numbered from 1 to 90. If one disc i...
Probability of drawing a disc with:
a) Two-digit number is a perfect square number:
- There are 9 perfect square numbers between 1 to 90, which are 1, 4, 9, 16, 25, 36, 49, 64, and 81.
- The total number of two-digit numbers between 1 to 90 is 90 - 9 = 81 (as we exclude single-digit numbers).
- Therefore, the probability of drawing a disc with a two-digit number that is a perfect square number is 9/81 = 1/9.
b) A number divisible by 5:
- There are 18 numbers between 1 to 90 that are divisible by 5 (5, 10, 15, ..., 85, 90).
- The total number of discs in the box is 90.
- Therefore, the probability of drawing a disc with a number divisible by 5 is 18/90 = 1/5.
Explanation:
- To find the probability of an event, we divide the number of favorable outcomes by the total number of outcomes.
- In this case, the favorable outcomes are the discs with numbers that satisfy the given conditions, and the total outcomes are the total number of discs in the box.
- By calculating the probabilities for each condition, we can determine the likelihood of drawing a disc with a specific number.
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