To calculate the number of moles of aluminium sulphate that contain 0.24 mole of oxygen atoms, we need to use the balanced chemical equation for the reaction involving aluminium sulphate and oxygen.



2Al2(SO4)3 + 3O2 → 2Al2O3 + 6SO3

From the balanced equation, we can see that 3 moles of oxygen react with 2 moles of aluminium sulphate. Therefore, the ratio of moles of oxygen to moles of aluminium sulphate is:

3 moles of oxygen : 2 moles of aluminium sulphate



Given that the number of moles of oxygen atoms is 0.24 mole, we can calculate the number of moles of aluminium sulphate using the above ratio:

(2/3) x 0.24 = 0.16 moles of aluminium sulphate

Therefore, 0.16 moles of aluminium sulphate will contain 0.24 mole of oxygen atoms.



To calculate the number of moles of a substance in a chemical reaction, we need to use the balanced chemical equation and the stoichiometric ratios. In this case, we used the ratio of moles of oxygen to moles of aluminium sulphate to calculate the number of moles of aluminium sulphate containing 0.24 mole of oxygen atoms.

0.02 mol