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Two thin lenses of power 3d and -2d are placed at contact then power and focal length of lens combination is?
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Power and Focal Length of Lens Combination


When two thin lenses are placed in contact, the power and focal length of the lens combination can be calculated using the following formulas:



  • Power: The power of the lens combination is given by the sum of the powers of the individual lenses.

  • Focal Length: The focal length of the lens combination is given by the reciprocal of the sum of the reciprocals of the individual focal lengths.



Using the given values:



  • Power of first lens, P1 = 3d

  • Power of second lens, P2 = -2d



We can calculate the power of the lens combination as:



  • Power of lens combination, P = P1 + P2

  • P = 3d + (-2d) = d



Therefore, the power of the lens combination is d.


To calculate the focal length of the lens combination, we use the formula:



  • Focal length of lens combination, f = 1 / ((1 / f1) + (1 / f2))



Where:



  • f1 = focal length of first lens

  • f2 = focal length of second lens



Since we know that:



  • f1 = 1 / P1

  • f2 = 1 / P2



We can substitute the values and calculate the focal length of the lens combination as:



  • f = 1 / ((1 / f1) + (1 / f2))

  • f = 1 / ((1 / (1 / P1)) + (1 / (1 / P2)))

  • f = 1 / ((1 / (1 / 3d)) + (1 / (1 / (-2d))))

  • f = 1 / ((1 / 3d) + (1 / -2d))

  • f = 1 / ((-2 / 6d) + (-3 / 6d))

  • f = 1 / (-5 / 6d)

  • f = -6d / 5



Therefore, the focal length of the lens combination is -6d / 5.
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