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A negative sign in the magnification value indicate that the image is _________
  • a)
    Real and inverted
  • b)
    Real and erect
  • c)
    Virtual and erect
  • d)
    Virtual and inverted
Correct answer is option 'A'. Can you explain this answer?
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A negative sign in the magnification value indicate that the image is ...
A negative sign in the magnification value indicate that the image is real and inverted.
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Answer:

To understand why a negative sign in the magnification value indicates that the image is real and inverted, we need to have a clear understanding of what magnification is and how it is calculated.

Magnification:
Magnification is a measure of how much larger or smaller an image appears compared to the object. It is given by the ratio of the height (or size) of the image to the height (or size) of the object. Mathematically, magnification (m) is defined as:

m = -v/u

Where:
- m is the magnification
- v is the image distance (distance of the image from the lens or mirror)
- u is the object distance (distance of the object from the lens or mirror)

Interpretation:
When the magnification value is positive, it indicates that the image is erect (upright) and virtual. This means that the image appears the same way as the object, but it is formed by the apparent intersection of the light rays rather than the actual path of light.

On the other hand, when the magnification value is negative, it indicates that the image is inverted. This means that the image is formed by the actual intersection of light rays and appears upside down compared to the object. In this case, the image is also real, which means that it can be projected onto a screen.

Therefore, a negative sign in the magnification value implies that the image is real and inverted.

Summary:
- When the magnification value is positive, the image is erect and virtual.
- When the magnification value is negative, the image is inverted and real.

Hence, the correct answer is option 'A' - Real and inverted.
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A negative sign in the magnification value indicate that the image is _________a)Real and invertedb)Real and erectc)Virtual and erectd)Virtual and invertedCorrect answer is option 'A'. Can you explain this answer?
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