The pairs of equations 9x + 3y + 12 = 0 and 18x + 6y + 26 = 0 havea)Un...
Given, 9x + 3y + 12 = 0 and 18x + 6y + 26 = 0
a1/a2 = 9/18 = 1/2
b1/b2 = 3/6 = 1/2
c1/c2 = 12/26 = 6/13
Since, a1/a2 = b1/b2 ≠ c1/c2
So, the pairs of equations are parallel and the lines never intersect each other at any point, therefore there is no possible solution.
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The pairs of equations 9x + 3y + 12 = 0 and 18x + 6y + 26 = 0 havea)Un...
Given equations are 9x - 3y + 12 = 0 and 18x - 6y + 26 = 0.
To find the solution, we can simplify the equations by dividing both sides of each equation by 3. This gives us:
3x - y + 4 = 0 and 6x - 2y + 13/3 = 0
Now, we can use the method of elimination to solve for x and y. Multiplying the first equation by 2 and subtracting it from the second equation, we get:
(6x - 2y + 13/3) - 2(3x - y + 4) = 0
Simplifying this, we get:
-4y + 5/3 = 0
Solving for y, we get:
y = 5/12
Substituting this value of y in the first equation, we get:
3x - 5/12 + 4 = 0
Solving for x, we get:
x = -47/108
Therefore, the system of equations has no solution as x and y do not satisfy both equations simultaneously.
Hence, the correct answer is option C, i.e., "No solution."
The pairs of equations 9x + 3y + 12 = 0 and 18x + 6y + 26 = 0 havea)Un...
A = 9 , b = 3 and c= 12
A = 18 , B = 6 and C = 26
let us consider the property of No solution
a/A = b/B ≠ c/ C
9/ 18 = 3/6 ≠ 12/26
1/2=1/2≠12/26
hence, the given equation have no solution.
option C. is correct
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