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A cylindrical tub of radius 5 cm and length 9.8 cm is full of water. A solid in the form of a right circular cone mounted on hemisphere is immersed into the tub. If the radius of hemisphere is 3.5 cm and height of cone outside the hemisphere is 5 cm. use pi = 22/7
The volume of solid immersed in the tub is
(A) 770 cm3
(B) 154 cm3
(C) 616 cm3
(D) 196 cm3?
The volume of solid immersed in the tub is
(A) 770 cm3
(B) 154 cm3
(C) 616 cm3
(D) 196 cm3?
Most Upvoted Answer
A cylindrical tub of radius 5 cm and length 9.8 cm is full of water. A...
**Given:**
- Radius of cylindrical tub = 5 cm
- Length of cylindrical tub = 9.8 cm
- Radius of hemisphere = 3.5 cm
- Height of cone outside the hemisphere = 5 cm
- Value of pi = 22/7
**To find:**
- Volume of solid immersed in the tub
**Solution:**
- Let's first find the volume of the solid.
- The solid is made up of a cone and a hemisphere.
- Volume of cone = 1/3 * pi * r^2 * h
- Here, radius of the cone (r) = 3.5 cm (same as the radius of the hemisphere)
- Height of the cone (h) = 5 cm (given)
- Volume of cone = 1/3 * 22/7 * 3.5^2 * 5 = 64.75 cm^3
- Volume of hemisphere = 2/3 * pi * r^3
- Here, radius of the hemisphere = 3.5 cm (given)
- Volume of hemisphere = 2/3 * 22/7 * 3.5^3 = 89.25 cm^3
- Total volume of the solid = Volume of cone + Volume of hemisphere = 64.75 + 89.25 = 154 cm^3
- Now, let's find the volume of water displaced by the solid.
- When the solid is immersed in the water in the tub, it displaces some water.
- The volume of water displaced is equal to the volume of the solid.
- Therefore, the volume of water displaced by the solid = 154 cm^3
- Hence, the volume of solid immersed in the tub is 154 cm^3.
- Therefore, the correct option is (B) 154 cm^3.
- Radius of cylindrical tub = 5 cm
- Length of cylindrical tub = 9.8 cm
- Radius of hemisphere = 3.5 cm
- Height of cone outside the hemisphere = 5 cm
- Value of pi = 22/7
**To find:**
- Volume of solid immersed in the tub
**Solution:**
- Let's first find the volume of the solid.
- The solid is made up of a cone and a hemisphere.
- Volume of cone = 1/3 * pi * r^2 * h
- Here, radius of the cone (r) = 3.5 cm (same as the radius of the hemisphere)
- Height of the cone (h) = 5 cm (given)
- Volume of cone = 1/3 * 22/7 * 3.5^2 * 5 = 64.75 cm^3
- Volume of hemisphere = 2/3 * pi * r^3
- Here, radius of the hemisphere = 3.5 cm (given)
- Volume of hemisphere = 2/3 * 22/7 * 3.5^3 = 89.25 cm^3
- Total volume of the solid = Volume of cone + Volume of hemisphere = 64.75 + 89.25 = 154 cm^3
- Now, let's find the volume of water displaced by the solid.
- When the solid is immersed in the water in the tub, it displaces some water.
- The volume of water displaced is equal to the volume of the solid.
- Therefore, the volume of water displaced by the solid = 154 cm^3
- Hence, the volume of solid immersed in the tub is 154 cm^3.
- Therefore, the correct option is (B) 154 cm^3.
Community Answer
A cylindrical tub of radius 5 cm and length 9.8 cm is full of water. A...
Volume of water in the tub=πr²h=π×5²×9.8cm³
volume of hemisphere= 2/3×π×3.5³cm³
volume of cone = 1/3π×3.5²×5cm³
Volume of water left in the tub = Volume of water in tub-Volume of toy.....
[ 2/3×π×3.5³ +1/3π×3.5²×5 ]
V=π(245−49)= 22/7×196 =22×8 = 616 cm³
HOPE IT HELPS YOU
volume of hemisphere= 2/3×π×3.5³cm³
volume of cone = 1/3π×3.5²×5cm³
Volume of water left in the tub = Volume of water in tub-Volume of toy.....
[ 2/3×π×3.5³ +1/3π×3.5²×5 ]
V=π(245−49)= 22/7×196 =22×8 = 616 cm³
HOPE IT HELPS YOU
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A cylindrical tub of radius 5 cm and length 9.8 cm is full of water. A solid in the form of a right circular cone mounted on hemisphere is immersed into the tub. If the radius of hemisphere is 3.5 cm and height of cone outside the hemisphere is 5 cm. use pi = 22/7 The volume of solid immersed in the tub is (A) 770 cm3 (B) 154 cm3 (C) 616 cm3 (D) 196 cm3?
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A cylindrical tub of radius 5 cm and length 9.8 cm is full of water. A solid in the form of a right circular cone mounted on hemisphere is immersed into the tub. If the radius of hemisphere is 3.5 cm and height of cone outside the hemisphere is 5 cm. use pi = 22/7 The volume of solid immersed in the tub is (A) 770 cm3 (B) 154 cm3 (C) 616 cm3 (D) 196 cm3? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about A cylindrical tub of radius 5 cm and length 9.8 cm is full of water. A solid in the form of a right circular cone mounted on hemisphere is immersed into the tub. If the radius of hemisphere is 3.5 cm and height of cone outside the hemisphere is 5 cm. use pi = 22/7 The volume of solid immersed in the tub is (A) 770 cm3 (B) 154 cm3 (C) 616 cm3 (D) 196 cm3? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A cylindrical tub of radius 5 cm and length 9.8 cm is full of water. A solid in the form of a right circular cone mounted on hemisphere is immersed into the tub. If the radius of hemisphere is 3.5 cm and height of cone outside the hemisphere is 5 cm. use pi = 22/7 The volume of solid immersed in the tub is (A) 770 cm3 (B) 154 cm3 (C) 616 cm3 (D) 196 cm3?.
A cylindrical tub of radius 5 cm and length 9.8 cm is full of water. A solid in the form of a right circular cone mounted on hemisphere is immersed into the tub. If the radius of hemisphere is 3.5 cm and height of cone outside the hemisphere is 5 cm. use pi = 22/7 The volume of solid immersed in the tub is (A) 770 cm3 (B) 154 cm3 (C) 616 cm3 (D) 196 cm3? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about A cylindrical tub of radius 5 cm and length 9.8 cm is full of water. A solid in the form of a right circular cone mounted on hemisphere is immersed into the tub. If the radius of hemisphere is 3.5 cm and height of cone outside the hemisphere is 5 cm. use pi = 22/7 The volume of solid immersed in the tub is (A) 770 cm3 (B) 154 cm3 (C) 616 cm3 (D) 196 cm3? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A cylindrical tub of radius 5 cm and length 9.8 cm is full of water. A solid in the form of a right circular cone mounted on hemisphere is immersed into the tub. If the radius of hemisphere is 3.5 cm and height of cone outside the hemisphere is 5 cm. use pi = 22/7 The volume of solid immersed in the tub is (A) 770 cm3 (B) 154 cm3 (C) 616 cm3 (D) 196 cm3?.
Solutions for A cylindrical tub of radius 5 cm and length 9.8 cm is full of water. A solid in the form of a right circular cone mounted on hemisphere is immersed into the tub. If the radius of hemisphere is 3.5 cm and height of cone outside the hemisphere is 5 cm. use pi = 22/7 The volume of solid immersed in the tub is (A) 770 cm3 (B) 154 cm3 (C) 616 cm3 (D) 196 cm3? in English & in Hindi are available as part of our courses for Class 10.
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A cylindrical tub of radius 5 cm and length 9.8 cm is full of water. A solid in the form of a right circular cone mounted on hemisphere is immersed into the tub. If the radius of hemisphere is 3.5 cm and height of cone outside the hemisphere is 5 cm. use pi = 22/7 The volume of solid immersed in the tub is (A) 770 cm3 (B) 154 cm3 (C) 616 cm3 (D) 196 cm3?, a detailed solution for A cylindrical tub of radius 5 cm and length 9.8 cm is full of water. A solid in the form of a right circular cone mounted on hemisphere is immersed into the tub. If the radius of hemisphere is 3.5 cm and height of cone outside the hemisphere is 5 cm. use pi = 22/7 The volume of solid immersed in the tub is (A) 770 cm3 (B) 154 cm3 (C) 616 cm3 (D) 196 cm3? has been provided alongside types of A cylindrical tub of radius 5 cm and length 9.8 cm is full of water. A solid in the form of a right circular cone mounted on hemisphere is immersed into the tub. If the radius of hemisphere is 3.5 cm and height of cone outside the hemisphere is 5 cm. use pi = 22/7 The volume of solid immersed in the tub is (A) 770 cm3 (B) 154 cm3 (C) 616 cm3 (D) 196 cm3? theory, EduRev gives you an
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