D and e are respectively the points on the sides ab and ac of a triang...
Given:
∆ABC in which DE // BC. AD = 2cm, BD = 3 cm and BC = 7.5 cm.
To find:
The length of DE
Since, DE is parallel to BC
→ angle ADE = angle ABC (corresponding angles)
→ angle AED = angle ACB (corresponding angles)
Hence, by AA criterion of similarity,
∆ADE ~ ∆ABC
ratio of corresponding sides of similar triangles are equal.
AD/AB = DE/BC
AB = AD + DB
AB = 2 + 3 = 5 cm
So,
2/5 = DE/7.5
DE = 2/5 x 7.5
DE = 2 x 1.5
DE = 3 cm.
Hence, the length of side DE is 3 cm.
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D and e are respectively the points on the sides ab and ac of a triang...
Understanding the Problem
In triangle ABC, we have points D and E on sides AB and AC, respectively. The key details provided are:
- AD = 3 cm
- BD = 5 cm
- BC = 12.8 cm
- DE is parallel to BC
Using the Basic Proportionality Theorem
Since DE is parallel to BC, we can apply the Basic Proportionality Theorem (also known as Thales' theorem), which states that if a line is drawn parallel to one side of a triangle, it divides the other two sides proportionally.
Calculating Proportions
1. Identify Segments:
- Total length of AB: AB = AD + BD = 3 cm + 5 cm = 8 cm.
2. Determine Ratios:
- The ratio of AD to AB is: AD / AB = 3 cm / 8 cm.
- This ratio also applies to DE and BC because DE is parallel to BC.
3. Set Up the Equation:
- If DE is x cm long, then according to the theorem:
x / BC = AD / AB
- Substituting the values:
x / 12.8 cm = 3 cm / 8 cm.
Solving for DE
To find x (the length of DE), cross-multiply:
- x * 8 = 3 * 12.8
- x * 8 = 38.4
- x = 38.4 / 8
- x = 4.8 cm.
Conclusion
The length of DE is 4.8 cm. This solution demonstrates the power of proportional relationships in similar triangles, highlighting the importance of parallel lines in geometric figures.
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