The value of k for which the system of linear equation x 2y=3,5x ky 7=...
The given system is
x + 2y – 3 = 0 ……(i)
5x + ky + 7 = 0 ……(ii)
Here, a1 = 1, b1 = 2, c1 = -3, a2 = 5, b2 = k and c2 = 7.
For the system, to be consistent, we must have
=> a1/a2 = b1/b2 ≠ c1/c2
=> 1/5 = 2/k ≠ -3/7
=> 1/5 = 2/k
=> k = 10
Hence, k = 10.
Your question is wrong, it should be:
Find the value of k for which the system of equations x + 2y – 3 = 0 and 5x + ky + 7 = 0 is inconsistent.
This question is part of UPSC exam. View all Class 10 courses
The value of k for which the system of linear equation x 2y=3,5x ky 7=...
Solution:
Given system of linear equation:
x + 2y = 3 ...(1)
5x + ky + 7 = 0 ...(2)
For the system to be inconsistent, the given equations must be parallel.
We can write equation (1) in slope-intercept form as:
y = -x/2 + 3/2
Comparing equation (2) with the slope-intercept form y = mx + b, we get:
m = 5 and b = ky/(-7)
For the system to be inconsistent, the slope of equation (2) should be -1/2 (same as equation (1)).
So, we have:
5 = -1/2
ky/(-7) = 3/2
Clearly, the first equation has no solution.
The second equation gives:
ky = -21/2
Therefore, the value of k for which the system of linear equation is inconsistent is k = -21/10.
Hence, the solution is as follows:
Answer: The value of k for which the system of linear equation x + 2y = 3 and 5x + ky + 7 = 0 is inconsistent is k = -21/10.