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At room temperature, the mole fraction of a solution is 0.25 and the vapour pressure of the solvent is 0.80 atm. Then the lowering of vapour pressure is
  • a)
    0.75
  • b)
    0.60
  • c)
    0.20
  • d)
    0.80
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
At room temperature, the mole fraction of a solution is 0.25 and the v...
**Given Data:**
Mole fraction of the solution (X) = 0.25
Vapour pressure of the solvent (Po) = 0.80 atm
**Calculation:**
The lowering of vapour pressure can be calculated using Raoult's Law, which states that the partial pressure of a solvent in a solution is directly proportional to its mole fraction in the solution.
The formula for calculating the lowering of vapour pressure is:
∆P = Po * X
Substitute the given values:
∆P = 0.80 * 0.25
∆P = 0.20 atm
**Therefore, the lowering of vapour pressure is 0.20 atm, which corresponds to option 'C'.**
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Community Answer
At room temperature, the mole fraction of a solution is 0.25 and the v...
ΔP=P∘×xΔP=0.80×0.25=0.2
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